Answer:
200 students were in the program
Step-by-step explanation:
The parent should know how to figure ...
170/85% = total/100%
This is the same as ...
total = 170/0.85 = 200
200 students were in the program.
_____
<em>Critical Thinking</em>
There are three declarative statements here. <em>There is no question</em>. We have made up a question to answer.
Another possible answer to the non-question could be, "The parent can ask his student how many students were in the program."
Answer:
Step-by-step explanation:
12n2+48n=−n3−64
Step 1: Subtract -n^3-64 from both sides.
12n2+48n−(−n3−64)=−n3−64−(−n3−64)
n3+12n2+48n+64=0
Step 2: Factor left side of equation.
(n+4)(n+4)(n+4)=0
Step 3: Set factors equal to 0.
n+4=0
n=−4
<span>An equation is a statement of equality „=‟ between two expression for particular</span>values of the variable. For example5x + 6 = 2, x is the variable (unknown)The equations can be divided into the following two kinds:Conditional Equation:<span>It is an equation in which two algebraic expressions are equal for particular</span>value/s of the variable e.g.,<span>a) 2x <span>= <span>3 <span>is <span>true <span>only <span>for <span>x <span>= 3/2</span></span></span></span></span></span></span></span></span><span> b) x</span>2 + x – <span> 6 = 0 is true only for x = 2, -3</span> Note: for simplicity a conditional equation is called an equation.Identity:<span>It is an equation which holds good for all value of the variable e.g;</span><span>a) (a <span>+ <span>b) x</span></span></span><span>ax + bx is an identity and its two sides are equal for all values of x.</span><span> b) (x + 3) (x + 4)</span> x2<span> + 7x + 12 is also an identity which is true for all values of x.</span>For convenience, the symbol „=‟ shall be used both for equation and identity. <span>1.2 Degree <span>of <span>an Equation:</span></span></span>The degree of an equation is the highest sum of powers of the variables in one of theterm of the equation. For example<span>2x <span>+ <span>5 <span>= <span>0 1</span></span></span></span></span>st degree equation in single variable<span>3x <span>+ <span>7y <span>= <span>8 1</span></span></span></span></span>st degree equation in two variables2x2 – <span> <span>7x <span>+ <span>8 <span>= <span>0 2</span></span></span></span></span></span>nd degree equation in single variable2xy – <span> <span>7x <span>+ <span>3y <span>= <span>2 2</span></span></span></span></span></span>nd degree equation in two variablesx3 – 2x2<span> + <span>7x + <span>4 = <span>0 3</span></span></span></span>rd degree equation in single variablex2<span>y <span>+ <span>xy <span>+ <span>x <span>= <span>2 3</span></span></span></span></span></span></span>rd degree equation in two variables<span>1.3 Polynomial <span>Equation <span>of <span>Degree n:</span></span></span></span>An equation of the formanxn + an-1xn-1 + ---------------- + a3x3 + a2x2 + a1x + a0<span> = 0--------------(1)</span>Where n is a non-negative integer and an<span>, a</span>n-1, -------------, a3<span>, a</span>2<span>, a</span>1<span>, a</span>0 are realconstants, is called polynomial equation of degree n. Note that the degree of theequation in the single variable is the highest power of x which appear in the equation.Thus3x4 + 2x3 + 7 = 0x4 + x3 + x2<span> <span>+ <span>x <span>+ <span>1 <span>= <span>0 , x</span></span></span></span></span></span></span>4 = 0<span>are <span>all <span>fourth-degree polynomial equations.</span></span></span>By the techniques of higher mathematics, it may be shown that nth degree equation ofthe form (1) has exactly n solutions (roots). These roots may be real, complex or amixture of both. Further it may be shown that if such an equation has complex roots,they occur in pairs of conjugates complex numbers. In other words it cannot have anodd number of complex roots.<span>A number <span>of the <span>roots may <span>be equal. Thus <span>all four <span>roots of x</span></span></span></span></span></span>4 = 0<span>are <span>equal <span>which <span>are <span>zero, <span>and <span>the <span>four <span>roots <span>of x</span></span></span></span></span></span></span></span></span></span>4 – 2x2 + 1 = 0<span>Comprise two pairs of equal roots (1, 1, -1, -1)</span>
Answer:
10x+1
Step-by-step explanation:
Reason 1 and 2 are the best answers
