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Alja [10]
2 years ago
11

HELP ASAP ILL GIVE YOU 13 points

Mathematics
1 answer:
lubasha [3.4K]2 years ago
3 0

Answer:

the domain and range can be found by horizontal and vertical test

Step-by-step explanation:

6.B

7.D

8.A

9.C

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A) Work out the value of 213 + (29)2
Alina [70]

a) 2^13 / 2^18

b) 216

6 0
3 years ago
The diameter of a circle measures 7 5/6 inches. What is the radius of the circle? Enter your answer as a mixed number in the box
andrew-mc [135]

The radius of the circle expressed as a mixed number is:  3\frac{11}{12} inches.

<h3>What is the Radius of a Circle?</h3>

Radius of a circle = half the measure of the diameter of a circle.

Given:

diameter of a circle = 7\frac{5}{6} inches

Therefore:

Radius of the circle = 1/2(7\frac{5}{6})

= 1/2(47/6)

= (1 × 47)/(2 × 6)

= 47/12

= 3\frac{11}{12} inches.

Therefore, the radius of the circle expressed as a mixed number is:  3\frac{11}{12} inches.

Learn more about radius of a circle on:

brainly.com/question/24375372

4 0
2 years ago
Help with this plzzzz
kati45 [8]

Answer:

point C

Step-by-step explanation:

both planes include point C so that is where they intersect

4 0
2 years ago
Read 2 more answers
Out of a salary of $4500, I kept 1/3 as savings. Out of the remaining money, I spend 50% on food and 20% on house rent. How much
jeka94

Answer:

$2100

Step-by-step explanation:

1/3 of 4500 is 1500

to find 1/3 of a number is to multiply by 1/3

1/3 * 4500 = 1500

$1500 is for savings

subtract 1500 from 4500

4500 - 1500 = 3000

the remaining money is $3000

to find 50% of something, divide by 2

3000/2 = 1500

$1500 is spent on food.

20% of 3000 is 600

to find 20% of something, multiply the decimal value (0.2)

0.2 * 3000 = 600

$600 are spent on rent.

$450 leftover

1500 + 600 = 2100

Food and rent cost $2100

hope this helps:)

3 0
2 years ago
What is the simplified form of 2/x^2-x - 1/x?
Pachacha [2.7K]

Answer:  \bold{(C)\ \dfrac{3 - x}{x(x-1)}}

<u>Step-by-step explanation:</u>

   \dfrac{2}{x^2-x}-\dfrac{1}{x}

=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}

=\dfrac{2}{x(x-1)}+\dfrac{-1}{x}\bigg(\dfrac{x-1}{x-1}\bigg)

=\dfrac{2}{x(x-1)}+\dfrac{-x+1}{x(x-1)}

=\dfrac{2-x+1}{x(x-1)}

=\dfrac{3-x}{x(x-1)}

8 0
3 years ago
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