Assuming the cylinder is closed at both ends
Surface area = 2 pi r^2 + 2 pi r h = 108
now h = r/2 so we have:-
2pi r^2 + pi r^2= 108
3 pi r^2 = 108
r^2 = 11.459
r = 3.385
so the height h = 1.693 m to nearest thousandth
Answer:
ntersecting lines DA and CE.
To find:
Each pair of adjacent angles and vertical angles.
Solution:
Adjacent angles are in the same straight line.
Pair of adjacent angles:
(1) ∠EBD and ∠DBC
(2) ∠DBC and ∠CBA
(3) ∠CBA and ∠ABE
(4) ∠ABE and ∠EBD
Vertical angles are opposite angles in the same vertex.
Pair of vertical angles:
(1) ∠EBD and ∠CBA
(2) ∠DBC and ∠EBA
Cos ( 390)
- 4 cot (-45)
Csc (60)
Hope this helps
