Question

Answer this please it’s for algebra 2

Answer 1

Part a)

P(junior) = (number of juniors)/(number total)

P(junior) = 235/705

P(junior) = 1/3 exactly

P(junior) = 0.33333 approximately

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Part b)

P(freshman and LG) = (number of freshman who have LG)/(number total)

P(freshman and LG) = 70/705

P(freshman and LG) = 14/141 exactly

P(freshman and LG) = 0.09929 approximately

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Part c)

n(junior) = number of juniors = 235

n(samsung) = number of people who have samsung = 274

n(junior and samsung) = number of juniors who have samsung = 93

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n(junior or samsung) = n(junior)+n(samsung)-n(junior and samsung)

n(junior or samsung) = 235+274-93

n(junior or samsung) = 416

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P(junior or samsung) = n(junior or samsung)/n(total)

P(junior or samsung) = 416/705 exactly

P(junior or samsung) = 0.59007 approximately

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Part d)

n(sophomore and apple) = number of sophomores who have apple

n(sophomore and apple) = 80

n(apple) = number of students who have apple

n(apple) = 261

P(sophomore | apple) = n(sophomore and apple)/n(apple)

P(sophomore | apple) = 80/261 exactly

P(sophomore | apple) = 0.30651 approximately

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Part e)

define the events

A = junior who has apple

B = junior who has samsung

C = person is a junior

n(A or B) = number of juniors who have apple or samsung

n(A or B) = n(A) + n(B) ... A and B assumed mutually exclusive

n(A or B) = 87+93

n(A or B) = 180

n(C) = 235

P( (Apple or Samsung) | Junior ) = n(A or B)/n(C)

P( (Apple or Samsung) | Junior ) = 180/235

P( (Apple or Samsung) | Junior ) = 36/47 exactly

P( (Apple or Samsung) | Junior ) = 0.76596 approximately