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3 years ago

I've been struggling a bit with Composite Figures. This is 2 ones I've really struggled with though so, could I have some help?

Mathematics

1 answer:

Natali5045456 [20]3 years ago

6 0

You are right with : Which shapes could a pentagon be decomposed into to find its area? Chose all that apply.
C. five triangles
D. one triangle and one trapezoid
And #2: Is (A) and (C)

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You have a bag of 12 blue marbles and 12 red marbles. each are labeled 1-12. so you have 24 marbles in total (1-12 for each colo

Softa [21]

Answer:

The probability of the first marble being blue and second being red is a 50/50 because you have 12 red and 12 blue so 50/50

Step-by-step explanation:

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3 years ago

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What is -4=r/20-5? <br> Is it r=20

castortr0y [4]

Answer:

r = 20

Step-by-step explanation:

-4 = r/20 - 5

-4 + 5 = r/20 - 5 + 5

1 = r/20

1 * 20 = r/20 * 20

r = 20

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3 years ago

What tables could be used to verify that the functions they represent are inverses of each other? Select two options

algol13

Answer: B and E

Step-by-step explanation:

I just took the assignment. :)

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2 years ago

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Mr. Huyck needs 8 gallons of punch for the school dance. How many<br> quarts of punch would he need?

koban [17]

32 bc eight times four equals 32

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3 years ago

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An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

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3 years ago