Answer:
(-2, -4)
Step-by-step explanation:
You can complete the square of the equation to get
y+(4/2)^2 = x^2+4x+(4/2)^2
y+4 = x^2 + 4x + 4
y+4 = (x+2)^2
y = (x+2)^2 - 4
This gives the form y = a(x-h)^2 + k where (h, k) is the vertex of the equation. You can also arrive at the same conclusion by making some observations of the equation. (x+2)^2 minimum value is going to be 0 since and negative values resulting from x+2 is going to become positive because of the square. So the minimum value is when x+2 is 0 or when x is equal to -2 and when it's at that minimum value of 0 it's going to have 4 subtracted from it which gives the vertex of (-2, -4)
Pretty sure it is D
if you solve for the intercepts you get these answers
y-intercept is 6
x intercept is 2
Answer:
the answer would be p= 15
Step-by-step explanation:
Answer:
y=2x-2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(8-4)/(5-3)
m=4/2
m=2
y-y1=m(x-x1)
y-4=2(x-3)
y=2x-6+4
y=2x-2
Answer:
-7/2 = -2(x-1/2)^2
Step-by-step explanation:
0 = –2x^2 + 2x + 3
Subtract 3 from each side
-3 = –2x^2 + 2x
Factor out the -2
-3 =- 2(x^2 -x)
Take the coefficient of x and divide by 2 and square it
-1 /2 = -1/2 ^2 = 1/4
Add it to each side Remember the -2 on the outside so we need to multiply it by -2
-2 *1/4 = -1/2
-3 -1/2= -2(x^2 -x +1/4)
-7/2 = -2(x^2 -x +1/4)
-7/2 = -2(x-1/2)^2
