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Y_Kistochka [10]
3 years ago
8

Ishiro bought a bag of 50 jellybeans. The table shows how many of each color were in the bag. Ishiro will pick one jellybean fro

m the bag without looking. What is the probability that the jellybean will be red?
helo me

Mathematics
1 answer:
marshall27 [118]3 years ago
4 0

Answer:

1 / 5

Step-by-step explanation:

n ( S ) = 5 + 12 + 8 + 10 + 15

n ( S ) = 50

Let R be the event of getting red jellybean.

n ( R ) = 10

P ( R ) = n ( R ) / n ( S )

= 10 / 50

P ( R ) = 1 / 5

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Consider three boxes with numbered balls in them. Box A con- tains six balls numbered 1, . . . , 6. Box B contains twelve balls
murzikaleks [220]

Answer:

a) 0.73684

b) 2/3

Step-by-step explanation:

part a)

P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)}

Using conditional probability as above:

(A,B,C)

Cases for numerator when:

P( A is 1 and exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1)

= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4})  + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) = 0.048611111

Cases for denominator when:

P( Exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1) + P(not 1, 1 , 1)

= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4})  + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) + (\frac{5}{6}*\frac{1}{12}*\frac{1}{4})= 0.0659722222

Hence,

P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)} = \frac{0.048611111}{0.06597222} \\\\= 0.73684

Part b

P ( B = 12 / A+B+C = 21) = \frac{P ( B = 12 and A+B+C = 21)}{P (A+B+C = 21)}

Cases for denominator when:

P ( A + B + C = 21) = P(5,12,4) + P(6,11,4) + P(6,12,3)

= 3*P(5,12,4 ) =3* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{96}

Cases for numerator when:

P (B = 12 & A + B + C = 21) = P(5,12,4) + P(6,12,3)

= 2*P(5,12,4 ) =2* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{144}

Hence,

P ( B = 12 / A+B+C = 21) = \frac{\frac{1}{144} }{\frac{1}{96} }\\\\= \frac{2}{3}

4 0
3 years ago
It takes 12 hours for a single hose to fill a large vat. When a second hose is added, the vat can be filled in 4 hours. How many
aksik [14]
<h3>Answer:</h3>

6 hours

<h3>Step-by-step explanation:</h3>

The two hoses together take 1/3 the time (4/12 = 1/3), so the two hoses together are equivalent to 3 of the first hose.

That is, the second hose is equivalent to 2 of the first hose. Two of the first hose could fill the vat in half the time one of them can, so 6 hours.

The second hose alone can fill the vat in 6 hours.

_____

The first hose's rate of doing work is ...

... (1 vat)/(12 hours) = (1/12) vat/hour

If h is the second hose's rate of doing work, then working together their rate is ...

... (1/12 vat/hour) + h = (1/4 vat/hour)

... h = (1/4 - 1/12) vat/hour = (3/12 -1/12) vat/hour = 2/12 vat/hour

... h = 1/6 vat/hour

so will take 6 hours to fill 1 vat.

8 0
3 years ago
What is 6,007,200 in expanded and word form?
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Six million seven thousand two hundred
7 0
3 years ago
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Which of the following lists is in order from smallest to largest?
IRINA_888 [86]

1/2 , 5/8, 7/11, 2/3

7 0
3 years ago
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The distance between the two islands shown on the map is 210 miles. A ruler measures the distance on the map is three 1/2 inches
BARSIC [14]
<span>210 miles equals 1 and 1/2 inches (3 1/2"s or 0.5"). 1 and 1/2" is equal to two 3/4" (3/4 + 3/4 = 1 and 1/2). 1.5" is equal to 210 miles, and 1.5" is equal to 2 * .75", you can divide 210 miles by two, which gives you 105 miles.</span>
8 0
3 years ago
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