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Lorico [155]
3 years ago
9

Which interval contains a local minimum for the grafted function? [-4, -2.5] [-2, -1] [1, 2] [2.5, 4]

Mathematics
1 answer:
olga_2 [115]3 years ago
7 0

Answer:

Last option [2.5, 4]

Step-by-step explanation:

The local minima of a function are the points where the slope of the curve is zero and the function reaches a minimum value.

If, on the contrary, the function reaches a maximum value, then that point is a local maximum.

Observe, for example, the point (3, -4). Note that a line tangent to that point would be horizontal, that is, of slope m = 0. This point is a minimum of the function, because there are no values x to the right x = 3 or to the left of x = 3 for which f(x)

Now we must search among the options that interval contains at this point.

The intervals [-4, -2.5] [-2, -1] do not contain any local minimum

The intervalor [1, 2] contains a local maximum.

The only interval that contains a local minimum is [2.5, 4], which contains the point (3, -4)

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7 0
3 years ago
Multiply. Check picture.
VashaNatasha [74]

The answer is 3x^4-13x^3-x^2-11x+6.

Solution:

Use algebraic identity: a^m\times a^n=a^{m+n}

For example: x^2\times x=x^{2+1}=x^3

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To multiply these equations.

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Combine like terms together.

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3 0
3 years ago
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Rzqust [24]
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Cross multiply:

4(x+4) = 3(3x+1)
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-5x = -13
x = -13/-5
x = 13/5
3 0
3 years ago
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olasank [31]
Hello : 
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5 0
3 years ago
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