Find rates of change until you find a constant.
dy/dx=1,2,3,4,5,6
d2y/dx2=1,1,1,1,1
So the acceleration, d2y/d2x, is constant. This means that this is a quadratic sequence of the form a(n)=an^2+bn+c. So we can set up a system of equations to solve for the values of a,b, and c. Using the first three points, (1,1), (2,2), and (3,4) we have:
9a+3b+c=4, 4a+2b+c=2, and a+b+c=1 getting the differences...
5a+b=2 and 3a+b=1 and getting this difference...
2a=1, so a=1/2 making 5a+b=2 become:
2.5+b=2, so b=-1/2, making a+b+c=1 become:
1/2-1/2+c=1, so c=1 so the rule is:
a(n)=0.5x^2-0.5x+1 or if you prefer to not have decimals
a(n)=(x^2-x+2)/2
Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
<span>step 1 :</span> 3 • (x - 9) - 30 = 0
<span>Step 2 :</span><span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out like factors :
3x - 57 = 3 • (x - 19)
<span>Equation at the end of step 3 :</span> 3 • (x - 19) = 0
<span>Step 4 :</span>Equations which are never true :
<span> 4.1 </span> Solve : 3 = 0
<span>This equation has no solution.
</span>A a non-zero constant never equals zero.
Solving a Single Variable Equation :
<span> 4.2 </span> Solve : x-19 = 0<span>
</span>Add 19 to both sides of the equation :<span>
</span> x = 19
One solution was found : <span> x = 19</span>
Answer:
y = 3
Step-by-step explanation:
The two inner right triangles are similar, thus the ratios of corresponding sides are equal, that is
= 
( cross- multiply )
y² = 63 ( take the square root of both sides )
y = 
= 
= 
× = 3
The time would be 1:24 pm
