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3 years ago

9x – 1= 10x + 9 What is x equal to

Mathematics

1 answer:

ivolga24 [154]3 years ago

4 0

Answer:

-10=x

Step-by-step explanation:

9x-1=10x+9

9x-10×=9+1

-x=10

x=-10

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Identify the angle between 0 and 360 degrees that is coterminal with the

Andrei [34K]

Answer:

option 2

Step-by-step explanation:

By repeatedly subtracting 360° from the given angle.

1155° - 360° = 795°

795° - 360° = 435°

435° - 360° = 75° ← coterminal angle

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3 years ago

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3 years ago

Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

$P(X>140)=P(Z>2)$

$P(X>140)=1-P(Z$

The Z-score value we get is from the Z-table,

$P(X>140)=1-0.9772$

$P(X>140)=0.0228$

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

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3 years ago

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3 years ago

Two cross roads ,each width 10m cut at right angle through the centre of a rectangular park of length 700m and breadth 300m and

Dafna11 [192]

Answer:

Step-by-step explanation:

Area of one road = 700 x 10

7000 sq m

area of another road

= 300 x 10 = 3000sq m

Total area of road

= 7000 + 3000 - 10 x 10

= 9900 sq m

Area of park

= 700 x 300

= 210000 sq m

less area of road

= 210000 - 9900

= 200100 sq m

= 200100 / 10000 hectare

= 20.01 hectare.

7 0

3 years ago