Answer:
x = 8
Step-by-step explanation:
Let's solve your equation step-by-step.
5x−6=3x+10
Step 1: Subtract 3x from both sides.
5x−6−3x=3x+10−3x
2x−6=10
Step 2: Add 6 to both sides.
2x−6+6=10+6
2x=16
Step 3: Divide both sides by 2.
2x
/2
=
16/
2
x=8
Answer: a - 4.512 hours
b - 1.94 hours
Step-by-step explanation:
Given,
a) A(t) = 10 (0.7)^t
To determine when 2mg is left in the body
We would have,
A(t) = 2, therefore
2 = 10(0.7)^t
0.7^t =2÷10
0.7^t = 0.2
Take the log of both sides,
Log (0.7)^t = log 0.2
t log 0.7 = log 0.2
t = log 0.2/ 0.7
t = 4.512 hours
Thus it will take 4.512 hours for 2mg to be left in the body.
b) Half life
Let A(t) = 1/2 A(0)
Thus,
1/2 A(0) = A(0)0.7^t
Divide both sides by A(0)
1/2 = 0.7^t
0.7^t = 0.5
Take log of both sides
Log 0.7^t = log 0.5
t log 0.7 = log 0.5
t = log 0.5/log 0.7
t = 1.94 hours
Therefore, the half life of the drug is 1.94 hours
20x+30y= c(total cost of money)
Part B: 20(10)+5(30)
200+150=$350
It will be d cause all you doing is rearranging everything
