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3 years ago

Find the equation of the line with slope = -6 and passing through (-6,32).write your equation

Mathematics

1 answer:

Lemur [1.5K]3 years ago

4 0

Point slope form says the line through (a,b) with slope m is

y - b = m(x - a)

Here that's

y - 32 = -6(x - -6)

y -32 = -6(x + 6) = -6x - 36

y = -6x - 4

Check:

-6(-6) - 4 = 36 - 4 = 32, good

Answer: y = -6x - 4

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RSB [31]

Answer:

The Box 1 and Box 2 are the same mass.

Explanation:

It caused both to change speed because they have both the same mass.

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3 years ago

Daniel created an intersection with his race track. One of the angles at the intersection is 55°. What are the three other angle

melomori [17]

Answer:

55, 125 and 125

Step-by-step explanation:

In this question, we are asked to find the other 3 angles in an intersection.

Please check attachment for what the diagram of the intersection might look like.

The intersection consists simply of 4 angles meeting at a point with the 2 angles on each side vertically opposite to the angles on the other side.

since one of the angles is 55, and we are having a straight line, the other angle would be 180-55 = 125.[ sum of angles on a straight line is 180]

These two angles are vertically opposite, this means that the other three angles are 55,125 and 125.

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3 years ago

Jackie cut a 2 yard spool into 5 equal lengths of ribbon what is the length of each ribbon in yards

ratelena [41]

2/5 yards
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5 0

3 years ago

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You have 350 feet of fencing to enclose a rectangular plot that borders on a river. If you do not fence the side along the river

IrinaVladis [17]

The length and width that will maximize the area are 175 ft and 87.5 ft respectively

The largest area that can be enclosed is 15312.5 ft²

<h3>Area of a rectangle</h3>

area = lw

where

l = length

w = width

The fencing is 350 ft it is use to enclose a rectangular plot with a river occupying one part.

Therefore,

perimeter = l + 2w

350 = l + 2w

l = 350 - 2w

area = (350 - 2w)w

(350 - 2w)w = 0

where

w = 0 or 175

average = 175/2 = 87.5

Hence, the max area is at w = 87.5 ft

Therefore,

l = 350 - 2(87.5) = 175 ft

length = 175 ft

width = 87.5 ft

Therefore,

area = 175 × 87.5 = 15312.5 ft²

Therefore, the largest area that can be enclosed is 15312.5 ft²

learn more on rectangle here: brainly.com/question/11630499

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2 years ago

Let f(x)=x2+6x+11.<br><br> What is the average rate of change from x = 5 to x = 8?

Korvikt [17]

Plug 8 into the equation and divide it by that equation but with 5 plugged in

$\frac{ {8}^{2} + 6(8) + 11}{ {5}^{2} + 6(5) + 11 }$

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3 years ago

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