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Gnom [1K]
3 years ago
9

Its forcing me to do this for some reason i just wamt to use the website bro

Mathematics
1 answer:
RoseWind [281]3 years ago
3 0
What's forcing you to do this
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A triangle has side lengths of 36 in, 27in, and 61 in. Classify it as acute, obtuse, or right.
Lady_Fox [76]
<span>When given 3 triangle sides, to determine if the triangle is acute, right or obtuse:1) Square all 3 sides.36, 27, 61 </span><span> <span> <span> 1,296, </span></span></span> <span> <span> <span> 729, </span></span></span> <span> <span> <span> 3,721 </span> </span> </span> <span><span> </span> </span> <span><span> </span> </span> <span><span>2) Sum the squares of the 2 shortest sides.1,296 + 729 = 2,025

3) Compare this sum to the square of the 3rd side.2,025 < 3,721
if sum > 3rd side²   Acute Triangleif sum = 3rd side²   Right Triangleif sum < 3rd side²   Obtuse TriangleTherefore, it is an Obtuse TriangleSource:http://www.1728.org/triantest.htm
</span></span>
7 0
3 years ago
A manufacturer cuts squares from the corners of a rectangular plece of sheet metal that measures 2 inches by 7 inches (see Figur
Vladimir79 [104]

Answer:

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The volume of the open-topped box is equal to

V=LWH

where

L=(7-2x)\ in\\W=(2-2x)\ in\\H=x\ in

substitute

V=(7-2x)(2-2x)x

Convert to expanded form

V=(7-2x)(2-2x)x\\V=(14-14x-4x+4x^{2})x\\V=14x-14x^2-4x^2+4x^{3}\\V=4x^{3}-18x^{2} +14x

using a graphing tool

Graph the cubic equation

Remember that

The domain for x is the interval -----> (0,1)

Because

If x>1

then

the width is negative (W=2-2x)

so

The maximum is the point (0.46,3.02)

see the attached figure

therefore

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

8 0
3 years ago
What is difference 6 1/4. And 5 1/2
Rama09 [41]
3/4 I believe since 6 1/4- 51/2 is 3/4
6 0
3 years ago
The volume of a gas with a pressure of 1.2 atm increases from 1.0 L to 4.0 L. What is the final pressure of the gas, assuming co
salantis [7]

Answer:

(b) 0.30 atm

Step-by-step explanation:

Given data

Initial pressure= 1.2atm

Initial volume= 1.0L

Final volume= 4.0L

Final pressure= ???

Let us apply the gas formula to find the Final pressure

P1V1= P2V2

Substitute

1.2*1= x*4

Divide both sides by 4

1.2/4= x

x= 0.3atm

Hence the final pressure is 0.3 atm

5 0
2 years ago
PLEASE HELP ME!!
Ludmilka [50]

Answer:

<h2>The population will reach 1200 after about 2.8 years</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

The population of a certain species of bird in a region after t years can be modeled by the function P(t) = 1620/ 1+1.15e-0.42t , where t ≥ 0. When will the population reach 1,200?

According to question we are to calculate the time t that the population P(t) will reach 1200.To do this we will substitute P(t) = 1,200 into the equation and calculate for the time 't'.

Given;

P(t) = \frac{1620}{1+1.15e^{-0.42t} } \\\\at \ P(t)= 1200;\\\\1200 =  \frac{1620}{1+1.15e^{-0.42t} }\\\\cross\ multiplying\\\\1+1.15e^{-0.42t} = \frac{1620}{1200} \\\\1+1.15e^{-0.42t}  = 1.35\\\\1.15e^{-0.42t} = 1.35-1\\\\e^{-0.42t} = \frac{0.35}{1.15}\\ \\e^{-0.42t}  = 0.3043\\\\Taking \ ln\ of\ both\ sides\\\\lne^{-0.42t}  = ln0.3043\\\\-0.42t = -1.1897\\\\t = \frac{-1.1897}{-0.42} \\\\t = 2.8 years\\\\

The population will reach 1200 after about 2.8 years

6 0
3 years ago
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