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Kitty [74]
3 years ago
8

Plz help....according to the graph

Mathematics
2 answers:
Levart [38]3 years ago
7 0
Hi the answer to this is 

 A - Vertical Asymptote
Natalka [10]3 years ago
6 0
A is most likely the answer.

Hope this Helped!

;D
Brainliest??
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Hi need help PLEASE
Mariulka [41]
The answer is B.


hope i helped
5 0
3 years ago
Cos (A+B) =1/5<br>COS (A-B) = 3/5<br>Then find tan (A-B)​
Soloha48 [4]

Answer:

tan (A-B)​ = ± 4/3

Step-by-step explanation:

COS (A-B) = 3/5

COS² (A-B) = (3/5)² = 9/25 = 1 - sin² (A-B)

sin² (A-B) = 1 - 9/25 = 16/25

sin (A-B) = ± 4/5

tan (A-B) = sin (A-B) / cos (A-B) = (± 4/5) / (3/5) = ± 4/3

4 0
3 years ago
If 'a' is a number lying between 0 and 1. then which of the following is in increasing order? a) a², a, √a b) a √a ,a² c) a²,√a,
viktelen [127]

Step-by-step explanation:

None of these,

a(under root),a, a(square)

this is the correct answer

5 0
3 years ago
Read 2 more answers
Each side of a square calendar is 19 inches long. What is the calendar's perimeter?
liberstina [14]

Answer:

a square has 4 sides each of those sides is 19in long perimeter is all around the square so you would add 19+19+19+19=79in

6 0
3 years ago
Read 2 more answers
In a game a player draws and replaces a card from a deck 2 times. The possible outcomes and payouts are shown. What is the
Goshia [24]

<u>Given</u>:

Given that in a game a player draws and replaces a card from a deck 2 times.

The possible outcomes and payouts are given.

We need to determine the expected value for someone playing the game.

<u>Expected value:</u>

The expected value for someone playing the game can be determined by

EV=(\frac{26}{52})(\$ 20)+(\frac{52}{52})(\$4)+(\frac{52}{52})(\$ 0)+(\frac{26}{52})(-\$12)

Simplifying the values, we have;

EV=(\frac{1}{2})(\$ 20)+(1)(\$4)+(1)(\$ 0)+(\frac{1}{2})(-\$12)

Dividing the terms, we get;

EV=\$ 10+\$4+\$ 0+-\$6

Adding, we have;

EV=\$ 8

Thus, the expected value for someone playing the game is $8

3 0
3 years ago
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