3 years ago

Plz help....according to the graph

Mathematics

2 answers:

Levart [38]3 years ago

7 0

Hi the answer to this is

A - Vertical Asymptote

Natalka [10]3 years ago

6 0

A is most likely the answer.

Hope this Helped!

;D
Brainliest??

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Hi need help PLEASE

Mariulka [41]

The answer is B.

hope i helped

5 0

3 years ago

Cos (A+B) =1/5 COS (A-B) = 3/5 Then find tan (A-B)

Soloha48 [4]

Answer:

tan (A-B) = ± 4/3

Step-by-step explanation:

COS (A-B) = 3/5

COS² (A-B) = (3/5)² = 9/25 = 1 - sin² (A-B)

sin² (A-B) = 1 - 9/25 = 16/25

sin (A-B) = ± 4/5

tan (A-B) = sin (A-B) / cos (A-B) = (± 4/5) / (3/5) = ± 4/3

4 0

3 years ago

If 'a' is a number lying between 0 and 1. then which of the following is in increasing order? a) a², a, √a b) a √a ,a² c) a²,√a,

viktelen [127]

Step-by-step explanation:

None of these,

a(under root),a, a(square)

this is the correct answer

5 0

3 years ago

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Each side of a square calendar is 19 inches long. What is the calendar's perimeter?

liberstina [14]

Answer:

a square has 4 sides each of those sides is 19in long perimeter is all around the square so you would add 19+19+19+19=79in

6 0

3 years ago

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In a game a player draws and replaces a card from a deck 2 times. The possible outcomes and payouts are shown. What is the

Goshia [24]

Given:

Given that in a game a player draws and replaces a card from a deck 2 times.

The possible outcomes and payouts are given.

We need to determine the expected value for someone playing the game.

Expected value:

The expected value for someone playing the game can be determined by

$EV=(\frac{26}{52})(\$ 20)+(\frac{52}{52})(\$4)+(\frac{52}{52})(\$ 0)+(\frac{26}{52})(-\$12)$

Simplifying the values, we have;

$EV=(\frac{1}{2})(\$ 20)+(1)(\$4)+(1)(\$ 0)+(\frac{1}{2})(-\$12)$

Dividing the terms, we get;

$EV=\$ 10+\$4+\$ 0+-\$6$

Adding, we have;

$EV=\$ 8$

Thus, the expected value for someone playing the game is $8

3 0

3 years ago