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RSB [31]
4 years ago
14

Jorge bought 3 DVDs, each for the same price, and a set of earphones for a price of $10. The total cost before tax was $49. What

was the cost of one DVD?
Mathematics
1 answer:
Ilia_Sergeevich [38]4 years ago
8 0

Answer:

The cost of each DVDs is $ 13   .

Step-by-step explanation:

Given as :

The cost of earphones = $ 10

The number of DVDs bought = 3

The total cost of both items before tax = $ 49

Let The cost of each DVDs = $ x

So, According to question

The cost of earphones + The cost of 3 DVDs  = $ 49

Or, $ 10 + 3 × x = $ 49

Or,  3 × x = $ 49 - $ 10

Or,  3 × x = $ 39

∴  x = \frac{39}{3}

I.e x = $ 13

Hence The cost of each DVDs is $ 13   . Answer

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<img src="https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7B12%7D%20%5Ctimes%20%5Csqrt%7B12%7D" id="TexFormula1" title="\sf \sqrt{12} \t
Darina [25.2K]

Answer:

12

Step-by-step explanation:

\sqrt{12} \times\sqrt{12}

\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{a}=a,\:\quad \:a\ge 0

\sqrt{12}\sqrt{12}=12

=12

7 0
3 years ago
Solve equation.<br> 13x + 41 = 16
sveta [45]

Answer:

x = -25/13

Step-by-step explanation:

Subtract 41 from 16 and divide the difference by 13

8 0
3 years ago
Read 2 more answers
A high school has 40 players on the football team. The summary of the players' weights is given in the box plot. Approximately,
yulyashka [42]

Answer:

About 91%

Step-by-step explanation:

According to the box plot provided :

Total number of students = 40

Minimum weight = 152 pounds

Third quartile (Q3) = 245

The approximate percentage of students that weigh 245 kg or less

About 10 of the intervals out of the 11 coverage interval of the box plot fall between 152 and 254 ; Hence,

(10 / 11) * 100

90.90

= about 91 % of the total students weigh 245 kg or less

4 0
3 years ago
A sample of n = 4 scores is obtained from a population with a mean of 70 and a standard deviation of 8. If the sample mean corre
jeka57 [31]

Answer:

The value of the sample mean is 78.

Step-by-step explanation:

We are given that a sample of n = 4 scores is obtained from a population with a mean of 70 and a standard deviation of 8.

Also, the sample mean corresponds to a z score of 2.00.

<em>Let </em>\bar X<em> = sample mean</em>

The z-score probability distribution for a sample mean is given by;

              Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = 70

            \sigma = standard deviation = 8

            n = sample size = 4

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

<u>Now, we are given that the sample mean corresponds to a z score of 2.00 for which we have to find the value of sample mean;</u>

So, <em><u>z-score</u></em> formula is given by ;

                  z-score = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } = \frac{\bar X-70}{\frac{8}{\sqrt{4} } }

                      2.00 =  \frac{\bar X-70}{\frac{8}{\sqrt{4} } }

                      2.00 =  \frac{\bar X-70}{4 } }

                     \bar X = 70+(2 \times 4)

                     \bar X = 70 + 8 = 78

<em>Therefore, the value of the sample mean is 78.</em>

3 0
3 years ago
A total of 679 tickets were sold for the school play. they were either adult tickets or student tickets. there were 71 fewer stu
guapka [62]
For example a stands for the number of adult tickets, and s stands for the number of student tickets.

Write a system of equation based on the problem
An equation for "<span>A total of 679 tickets were sold for the school play"
</span>∴ a + s = 679 <em>(first equation)</em>
An equation for "<span>there were 71 fewer student tickets sold than adult tickets"
</span>∴ s = a - 71 <em>(second equation)</em>
<span>
Find the solution of the system
Subtitute s with a - 71 in the first equation to find the value of a
a + s = 679
a + a - 71 = 679
2a - 71 = 679
2a = 679 + 71
2a = 750
  a = 750/2
  a = 375
The number of adult tickets sold is 375</span>
3 0
3 years ago
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