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RSB [31]
4 years ago
14

Jorge bought 3 DVDs, each for the same price, and a set of earphones for a price of $10. The total cost before tax was $49. What

was the cost of one DVD?
Mathematics
1 answer:
Ilia_Sergeevich [38]4 years ago
8 0

Answer:

The cost of each DVDs is $ 13   .

Step-by-step explanation:

Given as :

The cost of earphones = $ 10

The number of DVDs bought = 3

The total cost of both items before tax = $ 49

Let The cost of each DVDs = $ x

So, According to question

The cost of earphones + The cost of 3 DVDs  = $ 49

Or, $ 10 + 3 × x = $ 49

Or,  3 × x = $ 49 - $ 10

Or,  3 × x = $ 39

∴  x = \frac{39}{3}

I.e x = $ 13

Hence The cost of each DVDs is $ 13   . Answer

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no, 202 is not evenly divisible by 5

Step-by-step explanation:

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\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)
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The integral along the surface of the cylinder (with outward/positive orientation) is then

\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS
=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr
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And if you put that into A, y = 5x, it becomes 25 = 5(5)
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3 0
2 years ago
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