<span>19.2 x 10^8 minutes in hours is
32 000 000 hours
</span>
To start this question, we should know what is the atomic number of cobalt. The atomic number (the number of protons) of Cobalt is Z =27.
Now, we know that a Cobalt 60 isotope means an isotope of Cobalt whose Atomic Mass is 60.
Thus, in a Cobalt 60 isotope, the number of neutrons in the nucleus are

From the question we know that the given nuclear mass is 59.933820 u.
Now, the mass defect of Cobalt 60 can be easily calculated by adding the masses of the protons and the neutrons as per our calculations and subtracting the given nuclear mass from it.
Thus,
Mass Defect = (Number of Protons Mass of Proton given in the question) + (Number of Neutrons Mass of Neutron given in the question)-59.933820 u

Thus, the required Mass Defect is 0.5634u.
In eV, the Mass Defect is 
0.29m+10=0.35m
0.29m-0.29m+10= 0.35m-0.29m
10=0.06 m
Divide by 0.06 for 10 and 0.06
10/0.06= 0.06/0.06 m
m= 166.66666
Answer is m = 166.66666- the number 6 continues
Answer:
A
Step-by-step explanation:
Answer:
The confidence interval for 90% confidence would be narrower than the 95% confidence
Step-by-step explanation:
From the question we are told that
The sample size is n = 41
For a 95% confidence the level of significance is
and
the critical value of
is 
For a 90% confidence the level of significance is
and
the critical value of
is 
So we see with decreasing confidence level the critical value decrease
Now the margin of error is mathematically represented as
given that other values are constant and only
is varying we have that

Hence for reducing confidence level the margin of error will be reducing
The confidence interval is mathematically represented as

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value reduces, the margin of error reduces and the confidence interval becomes narrower