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Klio2033 [76]
3 years ago
14

Draw an angle in standard position whose terminal side contains the point

Mathematics
1 answer:
kvasek [131]3 years ago
5 0

Answer:

The distance of the point from the origin = 9.29 units.

Step-by-step explanation:

Given point:

(7,-6)

The angle lies such that the terminal side of the angle contains the given point.

To draw the angle and find the distance from the origin to the given point.

Solution:

The terminal side of the angle is where the angle ends with the initial side being the positive side of the x-axis.

So, we can plot the point (7,-6) by moving 7 units on the x-axis horizontally and -6 units on the y-axis vertically.

We can find the distance of the point from the origin by find the hypotenuse of the triangle formed.

Applying Pythagorean theorem.

Hypotenuse^2=Shorter\ Leg^2+Shortest\ Leg^2

Hypotenuse^2 = (7)^2+(-6)^2

Hypotenuse^2=49+36\\Hypotenuse^2=85

Taking square root both sides :

\sqrt{Hypotenuse^2}=\sqrt{85}

Hypotenuse = 9.29\ units

Thus, the distance of the point from the origin = 9.29 units.

The figure is shown below.

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
The diameter of a circle measures 32 mm. What is the circumference of the circle? Use 3.14 for , and do not round your answer. B
mart [117]

Answer:

100.48 ft

Step-by-step explanation:

8 0
2 years ago
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
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D. 7 miles

Step-by-step explanation:

26.5/4 =6.62

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3 years ago
Mrs. Aviles is planning a fruit-cup party for a class of 18 students and two teachers. She spends $10 for a package of snacks an
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Answer:this is the explanation of the question you have to put what they are asking you too

Step-by-step explanation:

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