Right. The first 5 is in the tenths place, the second five is in the hundredths, and the third one is in the thousandths. I'd like to think that if you take away (divide 1000 by ten) a tenth from the thousandths, that would leave you with the 5 in the middle being one tenth the value of the five to its right. (I'm not sure if this is correct or not, i'm just making an assumption). I would check with someone to make sure
Answer:
See below in bold.
Step-by-step explanation:
Let the length of the shortest side be x, then the longest side = 2x.
Also x + y = 2x + 1 where y = length of the middle side,
Simplifying:
2x - x - y = -1
x - y = -1 (A)
Also as the perimeter = 7:
x + 2x + y = 7
3x + y = 7 (B)
Adding (A) and (B):
4x + 0 = 6
x = 6/4 = 1.5
Plug x = 1.5 into equation B:
3(1.5) + y = 7
y = 7 - 4.5 = 2.5.
Answer:
So the shortest side = 1.5, middle = 2.5 and longest = 2*1.5 = 3.
<u>Given expression is </u>
can be rewritten as
We know,
And
So, using this identity, we
can be further rewritten as
<u>Hence, </u>
A number cube contains the numbers 1-6. Without counting the numbers that are less than two, you will get 3, 4, 5, and 6.