0.10d + 0.25q = 3.55
q = d + 3
0.10d + 0.25(d + 3) = 3.55
0.10d + 0.25d + 0.75 = 3.55
0.10d + 0.25d = 3.55 - 0.75
0.35d = 2.80
d = 2.80/0.35
d = 8.....8 dimes
q = d + 3
q = 8 + 3
q = 11 <=== 11 quarters
Let m=n-4
n - 4 + 5n = 20
6n = 24
> n = 4
m = 4 - 4
> m = 0
(0,4)
-12/-9=y/-4
cross multiply
-9y=48
divide by 9 on each side
y= -5.33
This can be solved by Newton's binomial formula
Tk+1 = (n k) a∧(n-k) b∧k k+1=7 => k=6, n=11 , a=-3x and b=-2y
T7= (11 6) (-3x)∧(11-6) (-2y)∧6 = (11*10*9*8*7)/(1*2*3*4*5) (-3x)∧5 (-2y)∧6
T7= 462 (-3x)∧5 (-2y)∧6
The correct answer is A.
Good luck!!!
Answer:
y = 6, RS = 35 and ST = 17
Step-by-step explanation:
Given that,
RS = 5y+5
ST = 2y+5
RT = 52
If we consider a number line,
RT = RS + ST
52 = 5y+5 + 2y+5
52 = 7y + 10
7y = 52-10
7y = 42
y = 6
RS = 5y+5
= 5(6)+5
= 35
ST = 2y+5
= 2(6) +5
= 17
Hence, this is the required solution.
