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Jlenok [28]
4 years ago
10

What is the solution of the linear-quadratic system of equations? y=x^2+5x-3 y-x=2

Mathematics
2 answers:
Nady [450]4 years ago
4 0
-x=-y+2
x=y-2
now substitute iin the first one
y=(y-2)^2+5 (y-2)-3
y=y^2-4y+4 +5y-10-3
y=y^2+y-9
y^2-9=0.
y^2=9
y=3

3-x=2
-x=2-3
-x=-1
x=1

the solution are x=1 and y=3
3=1^2+5 (1)-3
3=1+5-3
3=6-3
3=3
Rudiy274 years ago
3 0

Answer:

Step-by-step explanation:

-x=-y+2

x=y-2

now substitute iin the first one

y=(y-2)^2+5 (y-2)-3

y=y^2-4y+4 +5y-10-3

y=y^2+y-9

y^2-9=0.

y^2=9

y=3

3-x=2

-x=2-3

-x=-1

x=1

the solution are x=1 and y=3

3=1^2+5 (1)-3

3=1+5-3

3=6-3

3=3

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Answer:

E) x=0 or y=-5

Step-by-step explanation:

The slope field will have vertical segments when dy/dx is undefined, that is, dy/dx is a division by 0.

We have that

dy/dx=(3y)/(xy+5x)

So the slope field will have vertical segments when

xy + 5x = 0

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This is when x = 0 or y = -5.

So the correct answer is:

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Answer:

(a) The median is 1478

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Alternative hypothesis Hₐ : μ₁ > μ₂

(c) The test statistic  t_{\alpha/2} is 6.678155

(d) The p value is  1.2×10⁻¹¹

(e) We reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high

Step-by-step explanation:

(a) Here we have the data as follows;

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Therefore we have above the median  

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(b) Null hypothesis H₀ : μ₁ = μ₂

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t_{\alpha/2} =\frac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

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Critical z at 5% confidence level = 1.645

Since P << 0.05, e reject the

(e) Therefore, we reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high.

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