Answer:
Step-by-step explanation:
Simplify expression with rational exponents can look like a huge thing when you first see them with those fractions sitting up there in the exponent but let's remember our properties for dealing with exponents. We can apply those with fractions as well.
Examples
(a) 
From above, we have a power to a power, so, we can think of multiplying the exponents.
i.e.
Let's recall that when we are dealing with exponents that are fractions, we can simplify them just like normal fractions.
SO;
Let's take a look at another example
Here, we apply the 
to both 27 and 
Let us recall that in the rational exponent, the denominator is the root and the numerator is the exponent of such a particular number.
∴
![= \Bigg (\sqrt[3]{27}^{5} \times x^{10} }\Bigg)](https://tex.z-dn.net/?f=%3D%20%5CBigg%20%28%5Csqrt%5B3%5D%7B27%7D%5E%7B5%7D%20%5Ctimes%20x%5E%7B10%7D%20%7D%5CBigg%29)
Answer:
Left-most x-intercept: (-5,0)
Right-most x-intercept: (3,0)
Step-by-step explanation:
X-intercepts are also known as roots, when y = 0.
In this function, y = 0 when x = -5 and x = 3.
Answer:
d) Mr.Wallace can use the following equations:
a + b = 9
2 a + 3 b = 23
Step-by-step explanation:
Here, the total number of students = 23
Number of groups = 9
Each group can have 2 or 3 students.
a is the number of groups of 2.
⇒ Total students in a groups = a x (Number of student in each group)
= a x 2 = 2 a
b is the number of groups of 3
⇒ Total students in b groups = b x (Number of student in each group)
= b x 3 = 3 b
So, according to the question:
Total number of groups formed = 9
⇒ a + b = 9
Total number of students = 23
or Number of students in ( a group + b group ) = 23
⇒ 2 a + 3 b = 23
Hence, Mr.Wallace can use the following equations:
a + b = 9
2 a + 3 b = 23
Answer:
The correct option is;
False
Step-by-step explanation:
The coefficient of x^k·y^(n-k) is nk, False
The kth coefficient of the binomial expansion, (x + y)ⁿ is 
Where;
k = r - 1
r = The term in the series
For an example the expansion of (x + y)⁵, we have;
(x + y)⁵ = x⁵ + 5·x⁴·y + 10·x³·y² + 10·x²·y³ + 5·x·y⁴ + y⁵
The third term, (k = 3) coefficient is 10 while n×k = 3×5 = 15
Therefore, the coefficient of x^k·y^(n-k) for the expansion (x + y)ⁿ = 
not nk
