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Levart [38]
3 years ago
6

12(3-2x)=84 solve for x.

Mathematics
2 answers:
zimovet [89]3 years ago
8 0
12 (3-2x)=84
3-2x=84:12
3-2x=7
-2x=7-3
-2x=4
x=4:(-2)
x=-2
OlgaM077 [116]3 years ago
7 0
12(3-2x) = 84

do distributive multiplication:

12(3) + 12(-2x) = 84
36 - 24x = 84

Deduct 36 to both sides

36 - 36 - 24x = 84 - 36
-24x = 48

divide -24 to both sides

-24x / -24 = 48/-24
x = -2

To check:
12(3-2x) = 84
12(3-2(-2) = 84
12(3+4) = 84
12(7) = 84
84 = 84
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scoray [572]
The top row, on the right.

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8 0
3 years ago
Read 2 more answers
6 1⁄3 + 7 1⁄4 – 2 1⁄2 =
Korvikt [17]

Answer:

11 1/12

Step-by-step explanation:

6 1/3 = 19/3

7 1/4 = 29/4

2 1/2 = 5/2

19/3 + 29/4 - 5/2


We must find the LCM of 3, 4, and 2. This happens to be 12

3*4 = 12

4*3 = 12

2*6 = 12

Multiply each fraction by the factor that'll get it to 12.


19/3 * 4/4 = 76/12

29/4 * 3/3 = 87/12

5/2 * 6/6 = 30/12

Now go through the problem


76/12 + 87/12 - 30/12

76 + 87 = 163

163/12 - 30/12

163 - 30 = 133

133/12

Simplify

133/12 = 11.0833... or 11 1/12


Hope this helps.

6 0
3 years ago
Root of 108 is between______ and ______
natita [175]
Without using a calculator I would say the root is between 10 and 11 

How I found the answer:
I know 10 * 10 = 100
I know 11 * 11 = 121
So the root of 100 = 10 and the root of 121 = 11 so that means the root of 108 is somewhere between 10 and 11, which the root of 108 =  10.3923

5 0
3 years ago
Ilke is deciding whether to take his girlfriend on a dinner date or on a movie date the probability of this having a successful
Lerok [7]

Answer:

The dinner date

Step-by-step explanation:

5 0
3 years ago
Prime factorization of a 4- digit number with at least three distinct factors
denpristay [2]

Answer:

We know that every number can be written as a product of prime numbers.

The method to find the factorized form of a number depends on the number, we just try to find the different factors by dividing by them, for example for the number 1000 we have:

1000 is an even number, then we can divide it by 2 (2 is a prime number)

1000 = 2*500   (so we already found a prime factor)

500 is also an even number, so we can divide it by 2

1000 = 2*500 = 2*2*250  (we found another prime factor)

dividing by 2 again we get:

1000 = 2*2*250 = 2*2*2*125

1000 = (2*2*2)*125

now we just need to factorize 125

we know that 125 is a multiple of 5, such that:

125 = 5*25 = 5*5*5

(5 is a prime number, so it is completely factorized).

Then the factorization of 1000 is:

1000 = (2*2*2)*(5*5*5) = 2^3*5^3

Now with another example, 1422

1422 is an even number, so we again start using the factor 2:

1422 = 2 = 711

then:

1422 = 2*711

we already found a factor.

711 is a multiple of 3 (the sum of its digits is a multiple of 3), then:

711/3 = 237

We can write our number as:

1422 = 2*3*237

237 is also a multiple of 3

237/3 = 79

then:

1422 = 2*3*3*79

and 79 is a prime number, so we already have 1422 completely factorized.

8 0
2 years ago
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