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CaHeK987 [17]
3 years ago
11

A group of students organized a car wash to raise money for a local charity. The students charged $5.00 for each car they washed

. In 3 hours, they washed 12 cars. At that rate, how much money could they earn from washing cars for eight hours? and show how u got the answer please step by step
Mathematics
2 answers:
ladessa [460]3 years ago
5 0
12/3 = 4 4 cars per hour 4 x 5 = $20 20 x 8 = $160 for 8 hrs
pashok25 [27]3 years ago
3 0
First you would divide 12 cars by 3 hours to see how many cars get washed per hour
Then you know that 4 cars get washed in one hour so you multiply it by $5.00 because you want to see how much money they earn in one hour

After you know they earn $20.00 per hour you multiply that by 8 because you want to see how much money they earn in eight hours

So your final answer is $160 for washing cars in 8 hours
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State whether the triangles could be proven congruent, if possible, by SSS or SAS.
Helen [10]

Answer:

1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW  Given

Side FP ≅ Side CM     Given

Side YP ≅ Side MW    Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT   Given

Side SV ≅ Side SV  by reflexive property

Side VT ≅ Side VU   Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP  Given

Side MQ ≅ Side NP     Given

Side NQ ≅ Side NQ    by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL  Given

Side GJ ≅ Side HK     Given

∠JLG ≅ ∠HLK    vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW   Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ  by reflexive property

Side ZW ≅ Side ZY   Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

3 0
3 years ago
Help please . thank you
S_A_V [24]
PLEASE DONT USE THAT LINK
5 0
3 years ago
A pet store contains 35 light green parakeets (14 females and 21 males) and 44 sky blue parakeets (28 females and 16 males). You
snow_tiger [21]
You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB) 

Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)

Req:
- the probability that it is a female (F) or a sky blue (SB)

Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB) 
                 = [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
                 = 53.16 + 55.70 - 35.44
                 = 73.42%

You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%


7 0
3 years ago
Question is in image <br> In the diagram below, ST is parallel to PR
likoan [24]

Answer:

  D.

Step-by-step explanation:

There is nothing in the figure to indicate the triangles are isosceles. This eliminates answer choices A, B, C.

Answer choice D is a required step in the proof, but only gets part of the way. The triangle similarity means ...

  SQ/PQ = TQ/RQ

From here, you need to decompose each of the sides PQ and RQ into parts. Then you can get to the desired relationship.

  (PQ -PS)/PQ = (RQ -RT)/RQ . . . segment sum theorem

  1 - PS/PQ = 1 -RT/RQ . . . . . . . do the division

  -PS/PQ = -RT/RQ . . . . . . . . subtract 1 (subtraction property of equality)

  PS/PQ = RT/RQ . . . . . . . . multiply by -1 (multiplication property of equality)

5 0
3 years ago
Ok for this question you have to solve for m and show work
konstantin123 [22]
10 = 2/3m - 3/2m
2/3m - 3/2m = 10
m ( 2/3 - 3/2 ) = 10
-5/6m = 10
5m = -60
m = -12
3 0
3 years ago
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