Answer:
The length of each ribbon is 1.6 inches
Step-by-step explanation:
From the question, we are told that:
Kenedi has a piece of ribbon that measures 24 inches long. She cuts the ribbon into 15 equal pieces to attach to her dance costume
Hence, the expression that can be used to show how to calculate the length of each piece of ribbon is given as:
24 inches ÷ 15 pieces
= 24 ÷ 15
= 1.6 inches
Therefore, the length of each ribbon is 1.6 inches
The force exerted on victim is 20 newton
<em><u>Solution:</u></em>
An attacker swings a board with a mass of 2 kg toward a victim
The acceleration is 10 
when the board hits the victim
To find: Force exerted on victim
<em><u>The force is given by formula:</u></em>
From given,
<em><u>Substituting the values in formula,</u></em>
Thus force exerted on victim is 20 newton
2
3
−
1
1
=
3
+
3
2
3
x
−
11
=
x
3
+
3
32x−11=3x+3
2
3
−
1
1
=
3
+
3
2
x
3
−
11
=
x
3
+
3
32x−11=3x+3
2
Find common denominator
2
3
−
1
1
=
3
+
3
2
x
3
−
11
=
x
3
+
3
32x−11=3x+3
2
3
+
3
(
−
1
1
)
3
=
3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x+33(−11)=3x+3
3
Combine fractions with common denominator
2
3
+
3
(
−
1
1
)
3
=
3
+
3
2
x
3
+
3
(
−
11
)
3
=
x
3
+
3
32x+33(−11)=3x+3
2
+
3
(
−
1
1
)
3
=
3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)=3x+3
4
Multiply the numbers
2
+
3
(
−
1
1
)
3
=
3
+
3
2
x
+
3
(
−
11
)
3
=
x
3
+
3
32x+3(−11)=3x+3
2
−
3
3
3
=
3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33=3x+3
5
Find common denominator
2
−
3
3
3
=
3
+
3
2
x
−
33
3
=
x
3
+
3
32x−33=3x+3
2
−
3
3
3
=
3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33=3x+33⋅3
6
Combine fractions with common denominator
2
−
3
3
3
=
3
+
3
⋅
3
3
2
x
−
33
3
=
x
3
+
3
⋅
3
3
32x−33=3x+33⋅3
2
−
3
3
3
=
+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33=3x+3⋅3
7
Multiply the numbers
2
−
3
3
3
=
+
3
⋅
3
3
2
x
−
33
3
=
x
+
3
⋅
3
3
32x−33=3x+3⋅3
2
−
3
3
3
=
+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33=3x+9
8
Multiply all terms by the same value to eliminate fraction denominators
2
−
3
3
3
=
+
9
3
2
x
−
33
3
=
x
+
9
3
32x−33=3x+9
3
⋅
2
−
3
3
3
=
3
(
+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33=3(3x+9)
9
Cancel multiplied terms that are in the denominator
3
⋅
2
−
3
3
3
=
3
(
+
9
3
)
3
⋅
2
x
−
33
3
=
3
(
x
+
9
3
)
3⋅32x−33=3(3x+9)
2
−
3
3
=
+
9
2
x
−
33
=
x
+
9
2x−33=x+9
10
Add
3
3
33
33
to both sides of the equation
2
−
3
3
=
+
9
2
x
−
33
=
x
+
9
2x−33=x+9
2
−
3
3
+
3
3
=
+
9
+
3
3
2
x
−
33
+
33
=
x
+
9
+
33
2x−33+33=x+9+33
11
Simplify
Add the numbers
Add the numbers
2
=
+
4
2
2
x
=
x
+
42
2x=x+42
12
Subtract
x
x
from both sides of the equation
2
=
+
4
2
2
x
=
x
+
42
2x=x+42
2
−
=
+
4
2
−
2
x
−
x
=
x
+
42
−
x
2x−x=x+42−x
13
Simplify
Combine like terms
Multiply by 1
Combine like terms
=
4
2
x
