Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, 
So, the <u>speed of Pratap with the current</u> will be:
miles/hour
and the <u>speed of Pratap against the current</u> will be:
miles/hour.
Suppose, the rate of Pratap in still water is
and the rate of current is
.
So, the equations will be........

Adding equation (1) and (2) , we will get......

Now, plugging this
into equation (1), we will get.....

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
Combine like terms
8u+3u= 11u
and
9v-5v= 4v
So the answer is 11u+4v
Using the given function, it is found that the snowball traveled 4 feet when the height is 20 feet.
<h3>What is the function for the ball's height?</h3>
The height when x feet are traveled is given by:
h(x) = -0.5x² + 6x + 4.
When the height is of 20 meters, we have that h(x) = 20, hence:
20 = -0.5x² + 6x + 4.
0.5x² - 6x + 16 = 0
x² - 12x + 32 = 0
(x - 8)(x - 4) = 0
For the first time: x - 4 = 0 -> x = 4.
The snowball traveled 4 feet when the height is 20 feet.
More can be learned about functions at brainly.com/question/25537936
Answer:
6x-11y=-13
Step-by-step explanation:
(x1,y1)=(3/2,2) and (x2,y2)=(-4,-1)
y-y1= y2-y1/x2-x1 (x-x1)
y-2=-3/-11/2(x-3/2)
=6/11(x-3/2)
11(y-2)=6x-9
11y-22=6x-9
6x-11y=9-22
6x-11y=-13
Answer:
multiply 5*8 and you will get the answer... 40cm