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3 years ago

Find all polar coordinates of point p where p = (6, -pi/5)

1 answer:

4 0

Given a point in coordinates form $(r,\theta)$ , one can compute the cartesian form like this:
$(r\cos\theta,r\sin\theta )$
We have:
$r=6,\theta=-\dfrac{\pi}{5}$
We get the cartesian form then:
$\left(6\cos-\dfrac{\pi}{5},6\sin-\dfrac{\pi}{5}\right)$

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Solve 3 over x minus 3 equals the quantity of x over x minus 3, minus three-halves. for x and determine if the solution is extra

astraxan [27]

$\frac{3}{x} -3 = \frac{x}{x} - \frac{3}{2}$
$3 -3x = x - \frac{3x}{2}$
$-6x -2x -x = 6$
$-9x=6$
$9x=6$
$x= \frac{6}{9}= \frac{2}{3}$

3 0

3 years ago

How do you solve 69-3a=0

aleksandrvk [35]

69 - 3a = 0

69 - 3a (-69) = 0 (-69)

-3a = -69

-3a(/-3) = -69(/-3)

a = 23

hope this helps

8 0

3 years ago

Which of the following values are in the range of the function graphed below?

Dafna1 [17]

Answer:

A. 1

Step-by-step explanation:

I see only one red function line in the graph. this line represents the simple function y = 1, for x in the interval [-2,1].

the domain of a function defines the possible values for x, and the range of a function defined the possible values for y.

this function has only one possible value for y : 1

so, only A applies.

5 0

3 years ago

What is the Pythagorean theorem and how do I use it?

Leviafan [203]

I actually just learned this in 8th grade and it was so easy its crazy but its honestly simple it helps you solve the triangles and things and the equation is a squared + b squared = c squared and the a and b you would plug in the sides of the triangle or whatever shape your working with and square those numbers then find c by adding the two and then you square the c at the end and that will be your answer.

4 0

3 years ago

Read 2 more answers

Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3

aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= X[bar] - μ ~ $t_{n-1}$

S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= 3690 - 3300 = 2.549

530/√12

The rejection region for this test is two-tailed, with critical values:

$t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201$

$t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201$

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

7 0

3 years ago