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Harrizon [31]
3 years ago
13

2.5y; when y = -5.2

Mathematics
1 answer:
attashe74 [19]3 years ago
7 0
The answer is -13. You figure it out by multiplying 2.5×-5.2=13
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I just need help typing it out
Lena [83]
Ok so basically what u need to do is
7 0
2 years ago
investments historically have doubled every 9 years. If you start will a $2,000 investment, how much money would you have after
azamat

Answer:

$64,000

Step-by-step explanation:

Friday, 45 / 9 = 5

So the investment will double 5 times

First time

2,000 (starting investment) × 2 = 4000

Second time

4000 × 2 = 8000

Third time

8000 × 2 = 16000

Fourth time

16000 × 2 = 32000

Fifth and final time

32000 × 2 = 64000

$64,000

7 0
2 years ago
Ty in advance god bless
damaskus [11]

Step-by-step explanation:

3/7y + 3/4x = 3/5

y = -3/4x.7/3 +3/5.7/3

y = -7/4x +7/5

so the slope is -7/4

6 0
3 years ago
Read 2 more answers
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
I need help figuring out the slope to these points Y=-x-4
mash [69]

Answer:the slope is -1

Step-by-step explanation:

Comparing them equation to

y=mx+c where m is there slope

y=-x-4 the slope is -1

8 0
3 years ago
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