Answer:
Step-bThis is an interesting problem. To solve it I should find two irrational numbers r and s such that rs is rational.
I am not sure I am able to do that. However, I am confident that the following argument does solve the problem.
As we know, √2 is irrational. In particular, √2 is real and also positive. Then √2√2 is also real. Which means that it is either rational or irrational.
If it's rational, the problem is solved with r = √2 and s = √2.
Assume √2√2 is irrational. Let r = √2√2 and s = √2. Then rs = (√2√2)√2 = √2√22 = √22 = 2. Which is clearly rational.
Either way, we have a pair of irrational numbers r and s such that rs is rational. Or do we? If we do, which is that?
(There's an interesting related problem.)
Chris Reineke came up with an additional example. This one is more direct and constructive. Both log(4) and √10 are irrational. However
√10 log(4) = 10log(2) = 2.y-step explanation:
Is there a picture that suppose to come with this
Answer:
Distance is 200m between each pole
Step-by-step explanation:
First, convert the length of the road into meters
1km= 1000m
1000m +200m= 1200m
There are 6 poles on the side and they're equally spaced
Divide the length of the road by the number of poles to get the distance between the poles
Distance between poles= Length of road/ Number of poles
Distance between poles= 1200m/ 6 poles
Distance between poles= 200m
