Answer:
5.25 times
Step-by-step explanation:
Beverage A and Beverage B are sold in identical cans.
From the above question
Beverage A is 4% sugar.
The portion of Beverage B that is sugar is 0.21.
Converting Portion of sugar in Beverage B to percentage we have :
0.21 × 100
= 21%
How many times more sugar is in Beverage B than Beverage A?
This is calculated as:
% Beverage B/% Beverage A
= 21%/4%
= 5.25
Hence Beverage B has 5.25 times more sugar than Beverage A.
Answer:
White men diagnosed with stage IV prostatic adenocarcinoma within the age bracket of 70-79 are 1.27 times more likely to survive five years after the diagnosis of stage IV prostatic adenocarcinoma than black men.
Step-by-step explanation:
The exposure is race and the outcome is survival.
Race Alive Dead T
W 2337 3669 6006
B 344 782 1126
Relative Risk - 1.27
White men diagnosed with stage IV prostatic adenocarcinoma within the age bracket of 70-79 are 1.27 times more likely to survive five years after the diagnosis of stage IV prostatic adenocarcinoma than black men.
You have to find a common denominator. In this case it will be 486/324 = x/324. Then you would have to turn the 324 around. Then it will be 486/324 X 324. Which would be 486. Therefore. X = 486. Please tell me if I am wrong. Your welcome!
-Twix
