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ANEK [815]
3 years ago
15

Find the angle θθ between the vectors v=2i+kv=2i+k, w=j−3kw=j−3k.

Mathematics
1 answer:
kaheart [24]3 years ago
4 0
Hello : 
v . w = <span>| | v | | × </span><span>| | w | |  cos(</span><span>θ) ....(1)
v(2,0,1)   w(0,1,-3)

</span>v . w = (2)(0)+(0)(1)+(1)(-3) = - 3
| | v | |  = √((2)²+(0)²+(1)²) = <span>√5
</span>| | w |  =  √((0)²+(1)²+(-3)²) = √10
by (1) : 
cos(θ) = (v . w ) /  | | v | | × | | w | |

cos(θ) = = - 3/√50
θ =.....   calculate by 2ind function ( calculator)

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