Answer:

So then the expected value in the long run for this case would be 19 millions
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete. And is defined as:

For 
Solution to the problem
Let's define the random variable X as the expected return for a new drug.
For this case we expected a return of X=750 millions with a probability of 0.14. We assume that p is the probability of success for this case p =0.14.
And the probability of no success on this case would be q = 1-p = 1-0.14 =0.86. And the cost associated for this case would be X= -100 million
If we use the definition of expected value we have this:

So then the expected value in the long run for this case would be 19 millions
Answer:
0.305
0.097
Step-by-step explanation:
…..………....
Answer:
M
Step-by-step explanation:
The table of x, y values for a proportional relationship show that y is 0 when x is 0. This applies to the second table (M).
Answer:
Sample Response: An expression is written as a phrase and an equation is written as a statement. Equations are written as sentences with capitalization and punctuation. Expressions are written as phrases with no capitalization or punctuation. An equation has an equals sign and an expression does not.
Step-by-step explanation:
87 and 93
45 and 135
74 and 106