5x^2-40=0; solve by using square roots.
2 answers:
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Answer:
the x² test statistic 13.71
Option a) 13.71 is the correct answer.
Step-by-step explanation:
Given the data in the question;
Feeder 1 2 3 4
Observed visits; 60 90 92 58
data sample = 300
Expected = 300 / 4 = 75
the x² test statistic = ?
= ∑[ (
-
)²/
]
= [ (60 - 75)² / 75 ] + [ (90 - 75)² / 75 ] + [ (92 - 75)² / 75 ] + [ (58 - 75)² / 75 ]
= [ 3 ] + [ 3 ] + [ 3.8533 ] + [ 3.8533 ]
= 13.7066 ≈ 13.71
Therefore, the x² test statistic 13.71
Option a) 13.71 is the correct answer.
<h2>Answer:</h2>
The correct answer is: Option: A
A. 85, 78, 80, 108, 46, 66, 68, 82, 72, 68
<h2>Step-by-step explanation:</h2>It is given that:
The whisker ranges from 66 to 85.
The box ranges from 68 to 82 with the vertical bar inside the box at 75.
- Hence, the minimum value of the box plot is: 66
- Maximum value of box plot is: 85
Also,
- The first quartile or the lower quartile i.e.
is: 68
- The middle quartile or median i.e.
is: 75
- The upper quartile or third quartile i.e.
is: 82
Also, it is given that:
One dot mark above forty-six.
One dot mark above one hundred and eight.
A)
On arranging the data in increasing order after removing outliers 46 and 108 we have:
66 68 68 72 78 80 82 85
Hence, from this data we have:
Minimum value=66
maximum value=85
As all the values matches the value defined.
Hence, this option is correct.
B)
On arranging the data in increasing order after removing 46 and 108 we have:
66 68 68 70 70 80 82 85
Hence, from this data we have:
Minimum value=66
maximum value=85
As the value of .
Hence, this option is incorrect.
C)
On arranging the data in increasing order after removing 46 and 108 we have:
66 68 72 78 80 80 82 85
Hence, from this data we have:
Minimum value=66
maximum value=85
As the value of do not match.
Hence, this option is incorrect.
D)
On arranging the data in increasing order after removing 46 and 108 we have:
66 68 68 72 78 80 80 85
Hence, from this data we have:
Minimum value=66
maximum value=85
As the value of do not match.
Hence, this option is incorrect.