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IrinaVladis [17]
3 years ago
9

Find the product of 500 and 3.

Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0
" the product " means multiply

500 x 3 = 1500 <==
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11k - 8 = 11 + 8 ( k + 9 )
Alexus [3.1K]

Answer:

k = \frac{91}{3}

Step-by-step explanation:

Expand.

11k - 8 = 11 + 8k + 72

Simplify 11 + 8k + 72 to 8k + 83.

11k - 8 = 8k + 83

Add 8 to both sides.

11k + 8k + 83 + 8

Simplify 8k + 83 + 8 to 8k + 91.

11k = 8k + 91

Subtract 8k from both sides.

11k - 8k = 91

Simplify 11k - 8k to 3k.

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k = \frac{91}{3}

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Which speeds are equal to 1/2 mile per hour? Mark all that apply.
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Can a Math expert please solve this and explain their answers. Thanks
Rudik [331]

Answer:

  1. B
  2. 152°
  3. B
  4. A

Step-by-step explanation:

The measure of an arc is twice the measure of the inscribed angle that subtends that arc. A tangent is a special case where the chord that is one leg of the inscribed angle has a length of zero.

1. Short arc LJ is 2a°. Short arc LK is 2b°. Then arc JLK is 2(a+b)°, and short arc JK is ...

  arc JK = 360° -2(a +b)° . . . . . matches choice B

__

2. Long arc WY is twice the measure of "inscribed" angle WYZ, so is ...

  long ard WY = 2(104°) = 208°

Then short arc WY is ...

  arc WXY = 360° -208° = 152°

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3. The arc measures are double those of the corresponding inscribed angles. We can add up the arcs around the circle:

  (arc AB +arc BC) = 2×70° = 140° . . . inscribed angle relation

  (arc BC +arc CD) = 2×98° = 196° . . . inscribed angle relation

  arc AB + arc BC +arc CD +arc DA = 360° . . . . sum around the circle

Adding the first two equations with arc DA, we have ...

  (arc AB + arc BC) +(arc BC +arc CD) +arc DA = 360° +arc BC

  140° +196° +80° = 360° +arc BC

  416° -360° = arc BC = 56° . . . . . matches choice B

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4. Angle C and angle A are supplementary in this inscribed quadrilateral.

  angle C = 180° -98° = 82° . . . . . matches choice A

3 0
4 years ago
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