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netineya [11]
3 years ago
9

Are there less than 1 million exactly 1 million or greater than 1 million miligrams in a kilogram?

Mathematics
2 answers:
son4ous [18]3 years ago
7 0
Exactly one million grams are in a kilogram.
statuscvo [17]3 years ago
6 0
There are exactly <span>1 million milligrams in a kilogram</span>
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Lemur [1.5K]
6 and 2/3 that is the answer
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In ΔMNO, n = 78 cm, o = 14 cm and ∠M=12°. Find the length of m, to the nearest centimeter
STALIN [3.7K]

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64

Step-by-step explanation:

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sergiy2304 [10]

After reflected over  the triangle the point a become A = (-1,-6). The option c is correct.

According to the statement

we have given that the a triangle ABC at the points A=(1,6) B=(-3,5) C=(7,1), and we have to find the points of a when the triangle is first reflected over the y axis.

So, For this purpose

we know that the when the triangle is at the x axis then the point A is A=(1,6).

But when the triangles reflected over the y - axis then the point A goes to the negative side of the graph. In other  words whole of the triangle shift to the negative side of the graph. That's why the point become negative.

So, The option c is correct. After reflected over  the triangle the point a become A = (-1,-6)

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brainly.com/question/1675117

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4 0
2 years ago
A survey of 100 high school students provided this
HACTEHA [7]

Answer:

35/100

Step-by-step explanation:

You have to find how many juniors there are, so if you add 13, 20, and 2 you get 35. For the denominator you have to find the total number of students, so just add all of the numbers together to get 100. So there is a 35/100 chance that a randomly selected student is a junior.

5 0
1 year ago
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liubo4ka [24]

Answer:

\frac{511\,\,\sqrt{3} }{99}  which is an irrational number

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Recall that the repeating decimal 0.7373737373... can be written in fraction form as: \frac{73}{99}

Now, let's write the number 147 which is inside the square root in factor form to find if it has some perfect square factors:

147=7^2\,3

Then, 7 will be able to go outside the root when we compute the final product requested:

\frac{73}{99} \,*\,7\,\sqrt{3} =\frac{511\,\,\sqrt{3} }{99}

This is an irrational number due to the fact that it is the product of a rational number (quotient between 511 and 99) times the irrational number \sqrt{3}

5 0
3 years ago
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