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3 years ago

Can someone help me with number five ???

Mathematics

1 answer:

exis [7]3 years ago

5 0

Hey there! This is gonna actually be surprisingly simple even though it looks confusing!

Since the scale is perfectly balanced (it's completely flat because the weights are equal) you can use an = sign.

There are 3 cubes which weigh 9 ounces so 3 times 9 is 27 so on the left side you can put down a 27. Then there are 7 circles so so 7x can represent this. So that belongs on the left side as well SO for the left sides we can write this
27 + 7x = _______

Now for the right side. There are 5 cubes so 5 times 9 ounces is 45 so that belongs on the left. And then there is one cube so we can just right x. SO for the right side (combined with the other parts we know looks like this.
27 + 7x = 45 + x

NOW for the solving!
27 + 7x = 45 + x
subtract x from both sides
27 + 6x = 45
subtract 27 from both sides
6x = 18
then divide 6 from both sides
x = 3

So the circles are 3 ounces!!!!

I hope that helps! And feel free to ask me any questions!!

- mathwizzard3

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OleMash [197]

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6 0

3 years ago

Find integra of xlnxdx

Mademuasel [1]

Answer:

$\dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

$\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}$

Increase the power by 1, then divide by the new power.

Given indefinite integral:

$\displaystyle \int x \ln x \:\: \text{d}x$

To integrate the given integral, use Integration by Parts:

$\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}$

$\text{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}$

$\text{Let }\dfrac{\text{d}v}{\text{d}x}=x \implies v=\dfrac{1}{2}x^2$

Therefore:

$\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x \ln x\:\:\text{d}x & = \ln x \cdot \dfrac{1}{2}x^2-\int \dfrac{1}{2}x^2 \cdot \dfrac{1}{x}\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x -\int \dfrac{1}{2}x\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}\end{aligned}$

Learn more about integration here:

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5 0

2 years ago

Suppose the height of an 18 year old boy is normally distributed with mean 187cm fifteen percent of 18 year old boys have height

BARSIC [14]

Answer:

the probability that two 18 year old boys chosen at random will have heights greater than 185cm is 0.403

Step-by-step explanation:

P( x > 193) = 0.15

= 1- p(x less than or equal 193)

= 1 -p( z < (x- u) /sigma)

= 1- p( z< (193 - 187)/ sigma)

= 1- p( z< 6/ sigma)

P(z< 6/sigma) = 1 - 0.15

P(z < 6/sigma)= 0.85

6/sigma =1.036

Sigma= 6/1.036

Sigma= 5.79

P( x> 185) = 1- p( x< 185)

= 1- p (z < (185- 187)/5.79)

= 1- p( z< -0.345)

= 1- 0.365

= 0.635

P (x> 185) = 0.635 × 0.635

=0.403

3 0

3 years ago

A small business assumes that the demand function for one of its new products can be modeled by p = Cekx. When p = $40, x = 1000

Maru [420]

Answer:

C= 82.1116

k=-0.0007192

Step-by-step explanation:

$p=Ce^{kx}\\40=Ce^{k1000}\\30=Ce^{k1400}\\$

Applying logarithmic properties yields in the following linear system:

$ln(40) = ln(C) + 1000k\\ln(30) = ln(C) + 1400k$

Solving for k:

$ln(40) = ln(C) + 1000k\\ln(30) = ln(C) + 1400k\\400 k = ln(30)-ln(40)\\k=-0.0007192$

Solving for C:

$40=Ce^{-0.0007192*1000}\\C= \frac{40}{e^{-0.0007192*1000}}\\C=82.1116$

C= 82.1116

k=-0.0007192

6 0

3 years ago

Round to the nearest hundredth 5/8

Solnce55 [7]

Eighths and their multiples are common fractions which I recommend memorizing, but to actually solve this, you use the literal meaning of a fraction and divide 5 by 8. See the long-division below (it was surprisingly difficult to type, so I hope it helps!).

To round 0.625 to the nearest hundredth, we go to the second decimal place, which is 5, so we round up to 0.63.

3 0

3 years ago