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Anit [1.1K]
4 years ago
12

How do i evaluate the expression below????

D%5E%7B4%7D%20" id="TexFormula1" title=" {4}^{2} \times {4}^{4} " alt=" {4}^{2} \times {4}^{4} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Darina [25.2K]4 years ago
5 0
The answer is 4096.
You would start be adding the exponents to get 4^6.
Next you would do 4 times 4 times 4 times 4 times 4 times 4. This would get you 4096.
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4 years ago
What is the general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12)?
ki77a [65]

The general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12) is x²-4x+7.

<h3>What is the vertex form of a quadratic equation?</h3>

Vertex form of the quadratic equation is used to find the coordinate of vertex points at which it crosses its symmetry.

The standard equation of the vertex form of quadratic is given as,

y=a(x-h)^2+k

Here, (h, k) is the vertex point.

The vertex of quadratic at (2, 3) and passing through the point (5, 12). Put the value of vertex point in the above equation,

y=a(x-2)^2+3

As the quadratic passes through the point (5, 12). Thus, put the value of this point,

12=a(5-2)^2+3\\12-3=a(3)^2\\9=a\times9\\a=\dfrac{9}{9}\\a=1

Put the value of <em>a</em> in the above expression,

y=1(x-2)^2+3\\y=(x-2)^2+3\\y=x^2-4x+4+3\\y=x^2-4x+7

Thus, the general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12) is x²-4x+7.

Learn more about the vertex form here;

brainly.com/question/17987697

#SPJ1

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If m∠ADB=(6x−4)° and m∠BDC=(4x+24)°, find the value of x such that ∠ADC is a right angle.
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To make ∠ADC is a right angle, value of x will be 7.

From given figure, it is observed that Angle ADC is combination of two angles ADB and BDC.

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Since, ∠ADC is right angle.

 So,  ∠ADC=90 degree

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