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3 years ago

Help with math homework please.

Mathematics

1 answer:

Andru [333]3 years ago

4 0

Answer:

(6,0)

Step-by-step explanation:

Hello there!

The place where the two lines cross is the solution, and you'll writle that in x,y form. Since 6=x and there is no levitation of y, our answer is (6,0).

Have a great day, and mark me brainliest if I am most helpful!

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The graph of the line with the equation y = 1/2 * x + 4 crosses the x-axis at which of the following

svlad2 [7]

Answer:

Step-by-step explanation:

so we are looking for the x intercept (where the line crosses the x axis).

to do this, we sub in 0 for y and solve for x.

y = 1/2x + 4....sub in 0 for y

0 = 1/2x + 4

-1/2x = 4

x = 4 * -2

x = -8 <=== so it crosses the x axis at (-8,0)

5 0

3 years ago

At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

MAXImum [283]

Answer-

At $x= \frac{1}{2304e^4-16e^2}$ the curve has maximum curvature.

Solution-

The formula for curvature =

$K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}$

Here,

$y=4e^{x}$

Then,

${y}' = 4e^{x} \ and \ {y}''=4e^{x}$

Putting the values,

$K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}$

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

${k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}$

Now, equating this to 0

$(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}$

$\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}$

$\Rightarrow 2304e^{2x}-16e^{2x}-1=0$

Solving this eq,

we get $x= \frac{1}{2304e^4-16e^2}$

∴ At $x= \frac{1}{2304e^4-16e^2}$ the curvature is maximum.

6 0

2 years ago

Solve by factoring. m^2+6m+5=0

alina1380 [7]

Answer:

-1 and -5

Step-by-step explanation:

m^2 + 6m + 5 = 0 is factored to: (m + 1)(m + 5) = 0.

The zero product property states that one of the represented parenthesis must equal zero to satisfy the right side of the equation.

(m + 1) = 0

(-1 + 1) = 0

This means that one of the values for m is -1.

(m + 5) = 0

(-5 + 5) = 0

This means that one of the values for m is -5.

Moreover, the value of m by factoring is -1 and -5

3 0

3 years ago

Write the integral in one variable to find the volume of the solid obtained by rotating the first-quadrant region bounded by y =

Dovator [93]

Answer:

V = π ∫₀² (y² − 8y + 6√(2y)) dy

V = π ∫₀² (6x − 5x² + x³) dx

Step-by-step explanation:

y₁ = 0.5x²

y₂ = x

First, find the intersections of the curves.

0.5x² = x

x² = 2x

x² − 2x = 0

x (x − 2) = 0

x = 0 or x = 2

So the points of intersection are (0, 0) and (2, 2).

When we revolve this region about the line x = 3, we get a hollow shape that looks like an upside-down funnel, or a volcano.

One option is to use washer method to find the volume, by cutting a thin horizontal slice of thickness dy, inner radius 3−x₁ = 3−√(2y), and outer radius of 3−x₂ = 3−y.

V = ∫₀² π [(3−y)² − (3−√(2y))²] dy

V = ∫₀² π (9 − 6y + y² − 9 + 6√(2y) − 2y) dy

V = π ∫₀² (y² − 8y + 6√(2y)) dy

Another option is to use shell method to find the volume, by cutting a thin vertical slice of thickness dx, radius 3−x, and height y₂−y₁ = x−0.5x².

V = ∫₀² 2π (3 − x) (x − 0.5x²) dx

V = ∫₀² 2π (3x − 1.5x² − x² + 0.5x³) dx

V = ∫₀² 2π (3x − 2.5x² + 0.5x³) dx

V = π ∫₀² (6x − 5x² + x³) dx

The second option is arguably easier to evaluate, but either one will get you the same answer (V = 8π/3).

7 0

3 years ago

Please I need help and thx please show how you did it

rosijanka [135]

Answer:

1.) 9.2

2.)

625

633

the dealer

8.81

Step-by-step explanation:

I'm gonna assume that cm= compounded monthly

1.)

effective rate: .153/12= .01275

x= payments

$2590.67=300*\frac{1-(1+.01275)^{-x}}{.01275}\\.110103476=1-1.01275^{-x}\\.889896525=1.01275^{-x}\\\log_{1.01275}.889896525=-x\\x=9.207$

2.)

If there is no interest rate attached to financing through the deal the payment is just

37500/60 = 625

The monthly payment from the bank has a present value of 37500-3000=34500

and the effective rate is .039/12= .00325

$34500=x\frac{1-(1.00325)^{-60}}{.00325}\\34500=54.43234738x\\x=633.81$

Finally, the amount we save is just the difference

633.81-625=8.81

6 0

3 years ago

Read 2 more answers