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Georgia [21]
2 years ago
6

Complete the table below with the amounts of raspberry juice, apple

Mathematics
1 answer:
liq [111]2 years ago
7 0
So this is science. I would pick raspberry juice instead of apple because it’s right

Hope this helps!!
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HEEEEEELP !
iogann1982 [59]

If you meant to write y=23x-4 then none of the lines are perpendicular.

I suspect you intended y=2/3x-4, then line D, y=-3/2x-4 is perpendicular.

For any line y=mx+b, you have to "invert" m to get  a perpendicular line. Inverting in this case means: flip numerator and denominator and add a minus sign.

So 2/3 becomes -3/2, hence answer D.

The 'inverted' m is called the opposite reciprocal. That's your word of the day.


6 0
3 years ago
What is the slope of the line that goes through (2, 5) and (-6, -2) ?
alexira [117]
Answer:
slope = 7/8

Explanation:
Slope of the line can be calculated using the following equation:
slope = \frac{y2 - y1}{x2 - x1}

The two points given are:
(2,5) representing (x1 , y1)
(-6,-2) representing (x2 , y2)

Substitute with the points in the above equation to get the slope as follows:
slope = \frac{-2 - 5}{-6 - 2} = 7/8

Hope this helps :)

7 0
3 years ago
Please let me know ASAP
aksik [14]

Answer:

∠ BAC = 80°

Step-by-step explanation:

The sum of the interior angles of quadrilateral ACDB = 360°

DB and DC are tangents to the circle, thus

∠ DBA = ∠ ACD = 90° ( angle between tangent/ circle at point of contact )

Thus

∠ BAC + 90° + 90° + 100° = 360°

∠ BAC + 280° = 360° ( subtract 280° from both sides )

∠ BAC = 80°

4 0
3 years ago
Read 2 more answers
HELP!!!
Lady_Fox [76]

the construction of fields of formal infinite series in several variables, generalizing the classical notion of formal Laurent series in one variable. Our discussion addresses the field operations for these series (addition, multiplication, and division), the composition, and includes an implicit function theorem.


(PDF) Formal Laurent series in several variables. Available from: https://www.researchgate.net/publication/259130653_Formal_Laurent_series_in_several_variables [accessed Oct 08 2018].

8 0
3 years ago
Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA​
tekilochka [14]

Step-by-step explanation:

\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2}  }{sinA(1+cosA)} \\\\

\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\ and we have sin^{2}+cos^{2} =1

so \frac{1+1+2cosA  }{sinA(1+cosA)} \\\\

\frac{2+2cosA  }{sinA(1+cosA)} \\\\

\frac{2(1+cosA)}{sinA(1+cosA)} \\\\

\frac{2}{sinA} we have \frac{1}{sin}=cosec\\

<em>Finally </em>2cosecA<em />

<em>I really hope this helps coz it took much time </em>

3 0
3 years ago
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