Kdicneiddhd put more points worie dodveidhew

Length of the base = 8
Length of the hypotenuse = 17

The length of the third side ''
".


Using Pythagoras theorem, we have
(Perpendicular)² + (Base)² = (Hypotenuse)²
+ (8)² = (17)²
+ 64 = 289
= 289 - 64
= 225
= 
= 
Therefore, the length of the missing side
is
.

(15)² + (8)² = (17)²
225 + 64 = 289
289 = 289
L.H.S. = R. H. S.
Hence verified.

Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
1.2 is the slope of the line graphed in the given diagram
<u>Step-by-step explanation:</u>
We can use the given points (0, 3) and (-2.5, 0) to solve.
Slope formula is given by

Given two intercepts:

By substituting these in the slope equation, we get

1.5 because is 2 inches is 20 bags the it be 1 inch for 10 bags, so going half of 10 is 5 and 1 divided by 2 is .5... so add up the 10 bags and 5 bags to get an answer of 1.5 inches.