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4 years ago

You do not need to line up the decimal points when subtracting two decimal numbers. TrueFalse

Mathematics

2 answers:

Anvisha [2.4K]4 years ago

4 0

Answer:

False

Step-by-step explanation:

Or else it will give you an incorrect calculation

maw [93]4 years ago

3 0

Answer:

false

Step-by-step explanation:

You might be interested in

1. 9c-3c=48A) c=9B) c=3C) c=4D) C=8

Alona [7]

$9c\text{ - 3c = 48}$

To solve this equation, we need to subtract both, 9c - 3c:

$9c\text{ - 3c = 6c = 48}$

Dividing by 6 at both sides of the equation

$\frac{6c}{c}\text{ = }\frac{48}{6}$

Then

$c\text{ = 8}$

Then the answer C = 8. (Option D)

3 0

1 year ago

A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial,

Tresset [83]

Answer:

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

Step-by-step explanation:

Given - A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial, it will choose the same food on the next trial with a probability of 50%, and it will choose the other foods on the next trial with equal probabilities of 25%.

To find - If the animal chooses food #1 on an initial trial, what is the probability that it will choose food #2 on the second trial after the initial trial?

Proof -

By the given information, we get the stohastic matrix

$H = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]$

As we know that,

The matrix is a Markov chain $x_{k+1} = Hx_{k}$

Let

The initial state vector be

$x_{0} = \left[\begin{array}{ccc}1\\0\\0\end{array}\right]$

we choose this initial vector because given that If the animal chooses food #1 on an initial trial.

Now,

$x_{1} = Hx_{0} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}1\\0\\0\end{array}\right] \\= \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]$

∴ we get

$x_{1} = \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]$

Now,

$x_{2} = Hx_{1} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right] \\= \left[\begin{array}{ccc}0.25+0.0625+0.0625\\0.125+0.125+0.0625\\0.125+0.0625+0.125\end{array}\right]\\= \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]$

∴ we get

$x_{2} = \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]$

∴ we get

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

4 0

3 years ago

Students ages 10-17 were survey about their eating habits during breakfast

kap26 [50]

ok is there more info about it

6 0

3 years ago

Read 2 more answers

What is the value of x?

konstantin123 [22]

Answer:

X = 1

Step-by-step explanation:

X is none number but equals to 1

8 0

3 years ago

Read 2 more answers

Multiply(4×10^4)(3.63×10^-4) in scientifc notation

soldier1979 [14.2K]

Rewrite
(4)(3.63) * (10^4)(10^-4)
multiply
14.52 * (10^4)(10^-4)
multiplication of the coefficient is the addition of the exponent
so 4 -4 is 0

14.52

Hope this helps :)

5 0

4 years ago