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jeka57 [31]
3 years ago
8

Students ages 10-17 were survey about their eating habits during breakfast

Mathematics
2 answers:
larisa86 [58]3 years ago
7 0
There need to be the rest of the question
kap26 [50]3 years ago
6 0

ok is there more info about it

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At a soccer tournament 12 teams are wearing red shirts, 6 teams are wearing blue shirts, 4 teams are wearing orange shirts, and
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When you add 12, 6, 4 and 2, you will get 24. 12 of the 24 teams wear red shirts, so for every 2 teams there would be 1 team wearing red.

Hope this helped!

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An isosceles trapezoid has bases of lengths 6 and 8 and a height of 16. Find the area.
11111nata11111 [884]

Answer:

Step-by-step explanation:

In an isosceles trapezoid, the opposite sides are equal.

The formula for determining the area of a trapezoid is expressed as

Area = 1/2(a + b)h

Where

a and b are the length of The bases are the 2 sides of the trapezoid which are parallel with one another.

h represents the height of the trapezoid.

From the information given,

a = 6

b = 8

height = 16

Therefore,

Area of trapezoid = 1/2(6 + 8)16

= 1/2 × 14 × 16 = 112 square units

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3 years ago
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Julie has 6 crayons, Mark has seven times more than Julie. How many crayons does Mark have?
4 0
3 years ago
In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
WARRIOR [948]

Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

3 0
3 years ago
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