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pickupchik [31]
3 years ago
12

What is the length of a side of a cube with a volume of 729 m3?

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0
<span><span>the answer is a≈</span><span>9m </span></span><span>Volume <span>m3</span></span>
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A bus company charges $1.35 a kilometre for chartering a bus. Each bus can transport a maximum of 54 students. Assuming that the
WARRIOR [948]

Answer:

$1.25 is the answer in my opinion

7 0
3 years ago
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PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS PLS HELP ASAP ILL GIVE BRAINLKEST PLS
faltersainse [42]

Answer:

first one is 42/7 = 6

11*6 = 66

second one

1/2 inch = 3/2 feet

17/2 inches = 17*3 = 51/2 = 25.5

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2 years ago
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​78% of U.S. adults think that political correctness is a problem in America today. You randomly select six U.S. adults and ask
cupoosta [38]

Answer:

mean= 4.68

variance= 1.0296

Step-by-step explanation:

mean= n×p

n=6

p=0.78

mean= 6×(0.78)

           = 4.68

variance= n×p×(1-p)

             = 6 × 0.78×(1-0.78)

              = 1.0296

6 0
3 years ago
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Find, correct to the nearest degree, the three angles of the triangle with the given vertices. A(1, 0, −1), B(4, −3, 0), C(1
zavuch27 [327]

Answer:

Angle at vertex  A : 59.2° B: 61.7° C : 59.1°

Step-by-step explanation:

1. First find the length of the vectors  

AB = B-A = (4-1, 3-0, 0-1) = (3, 3, -1)

AC = C-A = (1-1, 4-0, 3-1) = (0, 4, 2)

BC = C-B = (1-4, 4-3, 3-0) = (-3, 1, 3)

2. Find magnitude of the vectors

|AB| = √(3^2+3^2+〖(-1)〗^2 )=√19  

|AC| = √(0^2+4^2+2^2 )=2√5

|BC| = √(〖(-3)〗^2+1^2+3^2 )=√19

3. Find the angles between them

cos θ = (a.b)/(|a||b|) -----> θ = arc cos ((a.b)/(|a||b|))

AB, AC : θ =arc cos (AB.AC)/(|AB||AC|) = arc cos ( (3.0+3.4+ -1.2)/(√19  x 2√5)=  10/(2√95) ) =59.136, which is approximately 59.14°

AB, BC : θ =arc cos (AB.BC)/(|AB||BC|) = arc cos( (3.-3+3.1+ -1.3)/(√19  x √19)=  (-9)/19 ) = 118.27°

Because of the direction of BC is pointing relative to AB this is the angle outside the triangle, and we should find the supplementary angle.

180-118.27 = 61.73°

If we used –(BC) = CB in the formula (just negate the numerator) we would have gotten the correct angle on first try.

The 3rd angle should be what’s left after subtracting from 180°;

180-61.73-59.14 = 59.13 °

You can confirm using the formula again :

AC, BC : θ =arc cos (AC.BC)/(|AC||BC|) = arc cos( (0.-3+4.1+ 2.3)/(√19  x 2√5)=  10/(2√95) = 59.13°

Rounding everything up so they add up to 180 degrees we have Angle at vertex  A : 59.2° B: 61.7° C : 59.1°

7 0
3 years ago
One side of trapezoid is 10 inches. The side parrellel to this is twice as long as this side. The height is half as long as the
madam [21]
The first side is 10 inches
the side parallel to this is (10×2)= 20 inches
Height is half the length=1/2×20=10 inches
The area of trapezium is given by:
Area=1/2×h×(a+b)
where a and b are the sides, h is the height. Thus the area will be:
Area=1/2×10×(20+10)
=1/2×10×30
=150 sq. inches
7 0
3 years ago
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