Find the dimensions of the rectangle meeting the specified conditions. The perimeter is 420 centimeters and the width is 30 cent
imeters less than the length.
1 answer:
Step-by-step explanation:
<h2>Let;</h2>
perimeter = 420cm
L = length
w = width
<h3>perimeter of rectangle = 2l +2w</h3>
420= 2l + 2w
<h3>but;</h3>
width = L - 30cm ( 30 cm less than length)
420cm = 2L + 2( L - 30cm)
420cm = 2L + 2L -60cm
420cm + 60cm = 2L + 2 L
480 Cm = 4L
L = 480cm ÷ 4
L = 120 cm
therefore, the length is 120 cm and width,
(L - 30cm)
= 120cm - 30cm
= 90cm
Therefore the width is also 90cm
You might be interested in
Answer:
(x-2)^1/4=2 ---> 18
√x^2+7=4. ---> -3
^3√1-x=-1. ---> 2
Step-by-step explanation:
just did it on plato
Answer:
42.06 ft²
Step-by-step explanation:
2 sides = 2(2.7 ft × 3.2 ft) = 2 × 8.64 ft² = 17.28 ft²
Front + back = 2(2.1 ft × 3.2 ft) = 2 × 6.72 ft² = 13.44 ft²
Top + bottom = 2(2.1 ft × 2.7 ft) = 2 × 5.67 ft² = <u>11.34 ft²
</u>
Total area = 42.06 ft²
$1.14 1.40 x 0.8=1.12 1.4+ 1.12=1.52 * 0.25 = 1.14
Answer:
um ok i do not know
Step-by-step explanation:
The answer is a Rational Number
