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bekas [8.4K]
3 years ago
15

Find the dimensions of the rectangle meeting the specified conditions. The perimeter is 420 centimeters and the width is 30 cent

imeters less than the length.
Mathematics
1 answer:
tia_tia [17]3 years ago
6 0

Step-by-step explanation:

<h2>Let;</h2>

perimeter = 420cm

L = length

w = width

<h3>perimeter of rectangle = 2l +2w</h3>

420= 2l + 2w

<h3>but;</h3>

width = L - 30cm ( 30 cm less than length)

420cm = 2L + 2( L - 30cm)

420cm = 2L + 2L -60cm

420cm + 60cm = 2L + 2 L

480 Cm = 4L

L = 480cm ÷ 4

L = 120 cm

therefore, the length is 120 cm and width,

(L - 30cm)

= 120cm - 30cm

= 90cm

Therefore the width is also 90cm

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Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

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C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

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