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viva [34]
3 years ago
8

Which fractions are greater than -5/16 ?

Mathematics
2 answers:
AlladinOne [14]3 years ago
3 0
-5/16 

Our choices:-

A.-3/8
 
 
 B.-11/12
 
 
 C.-1/4
 
 
<span> D.-1/8
</span>
Let us get all of them with a LCD

-1*2 = -2
8*2 = 16

-2/16 is not bigger than -5/16

-11/12 is bigger than -5/16 because half of 16 is 8.

-1*4 = -4
4*4= 16

-4/16 is not bigger than -5/16

-1/8 is smaller than -5/16

Final answer: -11/12 is the only fraction bigger than -5/16

saveliy_v [14]3 years ago
3 0
There are infinite fractions bigger than -5/16
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Can you please help me solve 18 and 21 please?
olya-2409 [2.1K]
<h3>Answer:</h3>

18. x = y = -3

21. y was substituted into the wrong equation. The solution is (x, y) = (2, 1).

<h3>Step-by-step explanation:</h3>

18. Adding y to the first equation transforms it to ...

... x = y

Then you can substitute for either variable in the second equation.

... 2y -5y = 9 . . . . . substitute for x

... -3y = 9 . . . . . . . . simplify

... y = -3 . . . . . . . . . divide by the coefficient of y

.. x = -3 . . . . . . . . . x and y have the same value

___

21. The first equation is being used to find an expression for y in terms of x. If you substitute that expression back into the same equation, it will tell you nothing you didn't already know. (Here, it is telling you 5 = 5.) The expression is only useful if you <em>substitute it into a different equation</em>. Here, it needs to be substituted into the second equation:

... <u>Step 2</u>: 3x -2(-2x+5) = 4 ⇒ 7x -10 = 4 . . . . . substitute for y in the second eqn

... <u>Step 3</u>: 7x = 14 . . . . . add 10

... <u>Step 4</u>: x = 2 . . . . . . . divide by 7

... <u>Step 5</u>: y = -2·2 +5 = 1 . . . . . find the value of y from x using the expression from step 1. Now, you know the solution is (x, y) = (2, 1).

_____

The attached graph shows the solution to the problem of 21.

4 0
4 years ago
Help pls wit algebra 2
NISA [10]

Answer:

C

Step-by-step explanation:

If R_A=3R_B, T_A+T_B=12, then

R_A=3R_B\\ \\T_A=12-T_B

Substitute them into the equation R_AT_A=360:

3R_B\cdot (12-T_B)=360\\ \\36R_B-3R_BT_B=360\\ \\12R_B-R_BT_B=120

Given R_BT_B=60, then

12R_B-60=120\\ \\12R_B=120+60\\ \\12R_B=180\\ \\R_B=15\\ \\15\cdot T_B=60\Rightarrow T_B=\dfrac{60}{15}=4\\ \\T_A=12-T_B=12-4=8\\ \\R_A\cdot 8=360\Rightarrow R_A=\dfrac{360}{8}=45

Hence,

R_A-R_B+T_A-T_B=45-15+8-4=30+4=34

5 0
3 years ago
Quick i need help now !
Alborosie

Answer:you need to know the amount of students I think

Step-by-step explanation:

5 0
3 years ago
Simplifica<br> (3x +5) (x -8)
Marrrta [24]
Um do you want that simplified you need to add more information or something
4 0
4 years ago
I don't understand this question, picture attached.
mina [271]

We can find this using the formula for arc length (where r is the radius of the circle and \theta is the central angle in radians):

\textrm{Arc Length} = r\theta


In our problem, we are given 12 = 8\theta. This means that:

\theta = \dfrac{12}{8} = \boxed{\frac{3}{2}}


The measure of the angle is 1.5.

5 0
4 years ago
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