When using substitution, you want to solve an equation for one variable that doesn’t make the equation worse to work with.
The general idea is that you want to find a variable that has a coefficient of 1 or -1.
In 2.5x - 7y = 7.5, both variables have “bad” coefficients.
In 6.2x - y = 1, the y has a coefficient of -1. That’s where you want to start.
Opposite of 10 is -10 then multiply by 4 which is -40 then subtract 30 which is -70
Answer:
y=x+4
Step-by-step explanation:
Slope is positive and it goes up by 1 so it is just 1 and the y-intercept is 4 so it is y=x+4
Answer:
![\large\boxed{D.\ (x-3)^2+(y+2)^2=81}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BD.%5C%20%28x-3%29%5E2%2B%28y%2B2%29%5E2%3D81%7D)
Step-by-step explanation:
The standard form of an equation of a circle:
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
(h, k) - center
r - radius
We have the center at (3, -2) and the radius r = 9. Substitute:
![(x-3)^2+(y-(-2))^2=9^2\\\\(x-3)^2+(y+2)^2=81](https://tex.z-dn.net/?f=%28x-3%29%5E2%2B%28y-%28-2%29%29%5E2%3D9%5E2%5C%5C%5C%5C%28x-3%29%5E2%2B%28y%2B2%29%5E2%3D81)
Answer:
Step-by-step explanation:
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