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alukav5142 [94]
3 years ago
11

For each geometric sequence, write a recursive rupe by finding the common ratio by calculating the ratio of consecutive terms. W

rite an explicit rule for the sequence by writing each term as the product of the first term and a power of the common ratio.​

Mathematics
1 answer:
slava [35]3 years ago
5 0

Answer:

3

Step-by-step explanation:

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What is the slope of the line that passes through the points (-3,-9) and (22,-4)
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Answer: 1/5

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X+2y=3 <br> 3y+5y=7 <br> I dont know
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Answer:

Step-by-step explanation:

3y+5y=8y

8y=7(divide 8 in both sides to get y)

y=7/8

x+2y=3...but we already know the value of y, so substitute 7/8 to y

x+2(7/8)=3

x+14/8=3

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=1.25

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Determine 3rd term in the geometric sequence whose first term is -8 and whose common ratio is 6
Brrunno [24]
-8, -48, -288
or
-8, -4/3, -2/9
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3 years ago
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An angle inscribed in the same os equal arc are equal?
Vadim26 [7]

Answer:

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Step-by-step explanation:

5 0
3 years ago
A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measurin
Ratling [72]

Answer:

The standard deviation of weight for this species of cockroaches is 4.62.

Step-by-step explanation:

Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

To find : What is the approximate standard deviation of weight for this species of cockroaches?

Solution :

We have given,

Mean \mu=50

The sample mean x=55

A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

i.e. P(X>55)=14%=0.14

The total probability needs to sum up to 1,

P(X\leq 55)=1-P(X>55)

P(X\leq 55)=1-0.14

P(X\leq 55)=0.86

The z-score value of 0.86 using z-score table is z=1.08.

Applying z-score formula,

z=\frac{x-\mu}{\sigma}

Where, \sigma is standard deviation

Substitute the values,

z=\frac{x-\mu}{\sigma}

1.08=\frac{55-50}{\sigma}

1.08=\frac{5}{\sigma}

\sigma=\frac{5}{1.08}

\sigma=4.62

The standard deviation of weight for this species of cockroaches is 4.62.

4 0
3 years ago
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