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katrin2010 [14]
4 years ago
5

The Daily Grind sells coffee makers. Its inventory of coffee makers without timers cost $20,000 and is now valued at $10,000. It

s inventory of coffee makers with timers cost $35,000 and is valued at $35,000. What is the value of the Daily Grind's inventory assuming it has 5 units of each type of coffee maker?
Business
1 answer:
zysi [14]4 years ago
5 0
Daily grinds inventory value = coffee maker with timer value x n units + coffee maker without timer in x  n units

where:
coffee maker with timer value = $35000 
coffee maker without timer = $10000 
n= 5 units each

Daily grinds coffee maker inventory value = ($35000 x 5)+( $10000 x 5)
                                                                   = $225000


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I did this in 7 th grade I don’t remeber government power
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3 years ago
Indicate whether the following actions would increase, decrease, or not affect Indigo Inc.'s total assets, liabilities, and stoc
Rufina [12.5K]

Answer:

                                              Assets       Liabilities      Stockholder's Equity

1. Authorizing and issuing   Not affect   Not affect        Not affect

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7 0
3 years ago
When would a productions possibilities frontier graph be used?
Romashka [77]

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6 0
3 years ago
Partners Ken and Macki each have a $40,000 capital balance and share income and losses in the ratio of 3:2. Cash equals $20,000,
tester [92]

Answer:

Partner Macki will eventually receive cash of $16,000

Explanation:

Macki has a $40,000 capital balance.

Income and losses ratio for Macki is 2

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Calculating for Macki

Cash to be received by partner Macki

= $40,000 * 2/5

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8 0
3 years ago
Read 2 more answers
National business machines manufactures x model a fax machines and y model b fax machines. each model a costs $100 to make, and
IrinaK [193]
<span>Profit needs to be maximized.
Profit = 30x+45y where x and y are respectively the number of model A and model B fax machines manufactured.

Objective function:
max(30x+45y)

 Constraints:
x≥0 ---------------(1)
y≥0 ---------------(2)
x+y ≤ 2500 since the demand is capped at 2500 -----------(3) 100x+150y≤600000 since manufacturing costs cannot exceed $600000-----(4)

 Solve the following two equations to identify where the two boundary lines (3) and (4) intersect.
x+y=2500-----(3)
100x+150y=600000---(4)

Multiplying (3) by 100
100x+100y=250000----(5)
(5)-(4)
50y=350000
y=7000
x=-4500

since the constraint states that x≥0, only three vertices are considered viz (0,0), (0,2500),(2500,0).

applying the profit function at each of the three vertices:
(0,0) ----- 30(0)+45(0) = 0
(0,2500) ---- 30(0)+45(2500)=112500
(2500,0) ---- 30(2500)+45(0)=75000

Hence by applying the max function, x=0, y=2500.
i.e. Dont produce any 'a' model machine. Manufacture 2500 units of model 'b' to maximise profit</span>
5 0
4 years ago
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