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pychu [463]
3 years ago
13

What is the value of n?

Mathematics
2 answers:
balu736 [363]3 years ago
3 0

I am not sure but I think it is d.


babymother [125]3 years ago
3 0

Answer: the answer is 69°




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Exhibit B In order to determine whether or not there is a significant difference between the hourly wages of two companies, two
ser-zykov [4K]

Answer: c. 3.01

Step-by-step explanation:

The test statistic for difference between two population mean (when population standard deviation is known) is given by :

z=\dfrac{\overline{x}_1-\overline{x}_2}{\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}}

, where n_1 = Size of first sample

n_2 = Size of second sample

\overline{x}_1-\overline{x}_2 = Difference between two sample mean.

\sigma_1 = standard deviation for population 1.

\sigma_2 = standard deviation for population 2.

As per given , we have

n_1=80

n_2=60

\overline{x}_1=\$6.75

\overline{x}_2=\$6.25

\sigma_1=\$1

\sigma_2=\$0.95

Substitute these values in formula , we get

z=\dfrac{6.75-6.25}{\sqrt{\dfrac{(1)^2}{80}+\dfrac{(0.95)^2}{60}}}

z=\dfrac{0.50}{\sqrt{0.0275416666667}}

z=\dfrac{0.50}{0.165956821694}

z=3.0128318613\approx3.01

Hence, the value of the test statistic is <u>3.01</u>.

Hence, the correct option is c. 3.01 .

7 0
3 years ago
Evaluate 3n - 4 for n = -2
mixer [17]
Okay so 3n- 4 =?
We have to insert the -2 into the problem where n is creating,
3(-2)-4=?
Then we simplify,
-6-4=?
Lastly the answer,
-10
3 0
3 years ago
What is the value of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B64%7D%20" id="TexFormula1" title=" \sqrt{64} " alt=" \sq
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8 as that means what two of the same number makes up , in this case 64. 8x8=64
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3 years ago
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GX is the angle bisector. Answer is C
4 0
3 years ago
Read 2 more answers
Solve for x. 3(3x - 1) + 2(3 - x) = 0
olga nikolaevna [1]
The equation given in the question is
3(3x - 1) + 2(3 - x) = 0
9x - 3 + 6 - 3x = 0
6x + 3 = 0
6x = - 3
x = - (3/6)
   = - (1/2)
So the value of x as has been determined above is -1/2. I hope the procedure is clear enough for you to understand.<span>You can always use this method for solving problems that are similar in type without requiring any help from outside. </span>



8 0
3 years ago
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