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RSB [31]
3 years ago
15

Each floor of a hotel as r rooms. On 8 floors, there are a total of 256 rooms. Write an equation to represent this situation

Mathematics
1 answer:
Natalka [10]3 years ago
3 0

Answer:

256/8 = r

Step-by-step explanation:

256 room between 8 floors so divide the number of rooms by each floor to work out r

256 divided by 8 equals r

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Answer:

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Step-by-step explanation:

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at the local aquarium, there are 10 dolphins 8 penguins, and 4 whales what is the ratio of pengiuns to whales
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10:4 because there are 10 dolphins and 4 whales
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I need to show the work. Please help
Juliette [100K]

Answer:

x=23

Step-by-step explanation:

The two angles are equal so you can set 8x-77 and 3x+38 equal to each other and write it as:

8x-77=3x+38

Then you get like terms on the same sides by subtracting 3x from both sides and getting:

5x-77=38

Then you add 77 to both sides and get:

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Then you divide both sides by 5 and get x=23

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3 years ago
Describe in your own words what it means to say that integers are closed under addition? (please help I don't get this question)
Naddik [55]

A set  that is closed under an operation or collection of operations is said to satisfy a closure  

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8 0
3 years ago
EXAMPLE 1 (a) Find the derivative of r(t) = (2 + t3)i + te−tj + sin(6t)k. (b) Find the unit tangent vector at the point t = 0. S
Tatiana [17]

The correct question is:

(a) Find the derivative of r(t) = (2 + t³)i + te^(−t)j + sin(6t)k.

(b) Find the unit tangent vector at the point t = 0.

Answer:

The derivative of r(t) is 3t²i + (1 - t)e^(-t)j + 6cos(6t)k

(b) The unit tangent vector is (j/2 + 3k)

Step-by-step explanation:

Given

r(t) = (2 + t³)i + te^(−t)j + sin(6t)k.

(a) To find the derivative of r(t), we differentiate r(t) with respect to t.

So, the derivative

r'(t) = 3t²i +[e^(-t) - te^(-t)]j + 6cos(6t)k

= 3t²i + (1 - t)e^(-t)j + 6cos(6t)k

(b) The unit tangent vector is obtained using the formula r'(0)/|r(0)|. r(0) is the value of r'(t) at t = 0, and |r(0)| is the modulus of r(0).

Now,

r'(0) = 3t²i + (1 - t)e^(-t)j + 6cos(6t)k; at t = 0

= 3(0)²i + (1 - 0)e^(0)j + 6cos(0)k

= j + 6k (Because cos(0) = 1)

r'(0) = j + 6k

r(0) = (2 + t³)i + te^(−t)j + sin(6t)k; at t = 0

= (2 + 0³)i + (0)e^(0)j + sin(0)k

= 2i (Because sin(0) = 0)

r(0) = 2i

Note: Suppose A = xi +yj +zk

|A| = √(x² + y² + z²).

So |r(0)| = √(2²) = 2

And finally, we can obtain the unit tangent vector

r'(0)/|r(0)| = (j + 6k)/2

= j/2 + 3k

8 0
3 years ago
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