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Kay [80]
3 years ago
7

Ceres is an asteroid with a mass of 8.7 x 10^20 kg that is 2.767 AU from the Sun. How many kilometers away is it from the Sun?

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
6 0

Answer:

Ceres is 4.15\times10^{8} km away from sun.

Step-by-step explanation:

We know that,

1 AU =1.50\times10^{8} Km

So, 2.767 AU in kilometers will be :

Applying the conversion of units:

2767\times(1.50\times10^{8})

= 415050000 km.

In exponential form we can re write this as :

4.15\times10^{8} kilometer.

Thus, Ceres is 4.15\times10^{8} kilometers away from the sun.

exis [7]3 years ago
4 0
In this problem the mass of the asteroid is completely irrelevant. To solve this we are going to take advantage of the fact the 1AU=<span>149,598,000 kilometers, so we can establish a conversion factor as follows:
</span>2.767AU* \frac{149598000km}{AU} =413937666
<span>
We can conclude that the asteroid is 413,937,666 kilometers away from the sun, or in scientific notation </span>4.139376660<span>·</span>10^8 kilometers away form the sun.
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sweet-ann [11.9K]

Answer:

(3x+1)(5x-2)

Step-by-step explanation:

Given the expression

15x^2-6x+5x-2

Factorize;

3x(5x-2)+ 1(5x-2)

(3x+1)(5x-2)

Hence the factorized form is (3x+1)(5x-2)

4 0
3 years ago
Expand each expression
matrenka [14]

Answer:

Option B - \ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Step-by-step explanation:

Given : Expression \ln(\frac{4y^5}{x^2})

To find : Expand each expression ?

Solution :

Using logarithmic properties,

\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B

and \ln (AB)=\ln A+\ln B

Here, A=4y^5 and B=x^2

\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}

\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2

\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2

Using logarithmic property, \logx^a=a\log x

\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Therefore, option B is correct.

3 0
3 years ago
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Properties of the normal distribution include?
V125BC [204]

Answer:

Properties of a normal distribution

The mean, mode and median are all equal.

The curve is symmetric at the center (i.e. around the mean, μ).

Exactly half of the values are to the left of center and exactly half the values are to the right.

The total area under the curve is 1.

Step-by-step explanation:

6 0
3 years ago
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stellarik [79]

Answer:

8 grams

Step-by-step explanation:

The balance is in equilibrium, so the weights of the two sides are equal.

Let the weight of a square be s.

Left side: 2s + 4

Right side: s + 3(4) = s + 12

The weights are equal, so we set the two expressions equal.

2s + 4 = s + 12

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Answer: The weight of a square is 8 grams.

8 0
4 years ago
A cake manufacturer boxes Swiss chocolate and German chocolate cakes at one site. A box of Swiss chocolate cake contains 0.55 lb
Kobotan [32]

Answer:

2,500 German chocolate cake boxes.

1,500 Swiss chocolate cake boxes.

Step-by-step explanation:

Let 'S' be the number of Swiss chocolate cakes boxed and 'G' the number of German cholocate cakes boxed. If all of the available ingredients are used:

0.55*S +0.59*G = 2,300\\0.45*S+0.41*G = 1,700

Solving the linear system above:

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2,500 German chocolate cake boxes and 1,500 Swiss chocolate cake boxes can be made each day.

6 0
4 years ago
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