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Kay [80]
3 years ago
7

Ceres is an asteroid with a mass of 8.7 x 10^20 kg that is 2.767 AU from the Sun. How many kilometers away is it from the Sun?

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
6 0

Answer:

Ceres is 4.15\times10^{8} km away from sun.

Step-by-step explanation:

We know that,

1 AU =1.50\times10^{8} Km

So, 2.767 AU in kilometers will be :

Applying the conversion of units:

2767\times(1.50\times10^{8})

= 415050000 km.

In exponential form we can re write this as :

4.15\times10^{8} kilometer.

Thus, Ceres is 4.15\times10^{8} kilometers away from the sun.

exis [7]3 years ago
4 0
In this problem the mass of the asteroid is completely irrelevant. To solve this we are going to take advantage of the fact the 1AU=<span>149,598,000 kilometers, so we can establish a conversion factor as follows:
</span>2.767AU* \frac{149598000km}{AU} =413937666
<span>
We can conclude that the asteroid is 413,937,666 kilometers away from the sun, or in scientific notation </span>4.139376660<span>·</span>10^8 kilometers away form the sun.
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Explain the difference between simple interest and compound interest.
USPshnik [31]

Simple interest:

 Simple interest is simple. Each year, the interest is calculated as a percentage of the principal, as follows: Interest= (principal) x (rate) x (time).

Compound interest:

Compound interest<span> is calculated on the principal amount and also on the accumulated </span>interest <span>of previous periods.</span>

8 0
3 years ago
2/3x - 1/2y = 3
nevsk [136]
2/3x - 1/2y = 3    |multiply both sides by 6

4x - 3y = 18

1/2x + y = 5    |multiply both sides by 2

x + 2y = 10

Answer: 4x - 3y and x + 2y = 10.
7 0
3 years ago
Cody and Brad bought pizza for the class party. Cody bought 12 pizzas for $15 each.
tankabanditka [31]

Answer:

brad paid more

Step-by-step explanation:

15/12=1.25

and 12/8=1.50

so brad paid more on pizza

3 0
3 years ago
Read 2 more answers
Last 2 tutor find it wrong pls help me
Mrac [35]

Answer:

  g(x) = 4x² -x +64

Step-by-step explanation:

The integral of f(x) will be continuous. This means the value must be the same for x = 4- as for x = 4+.

For some constant c1, the integral in the region x ≤ 4 is ...

  ∫f(x)dx = (4x² -x +c1) +C = g(x) +C

The integral in the region x ≥ 4 is given as ...

  ∫f(x)dx = 31x +C

Evaluated at x=4, we must get the same value from either expression:

  4(4²) -4 +c1 +C = 31(4) +C

  60 +c1 = 124

  c1 = 64

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In order to make the integral continuous at x=4, we must have ...

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4 0
3 years ago
The length of pregnancy isn’t always the same. In pigs, the length of pregnancies varies according to a normal distribution with
Nesterboy [21]

a. percent of pig pregnancies that are longer than 106 days

Since we have a normal distribution here and the average number of days is 106, we can say that 50% of the pig pregnancies are longer than 106 days.

b. percent of pig pregnancies that are shorter than 111 days

To get the percentage, we will have to convert x = 111 days into a z-score first. The formula is:

z=\frac{x-\mu}{\sigma}

where x = raw data, μ = population mean, and σ = population SD.

Since these 3 pieces of information are already given in the question, let's plug them into the equation above.

z=\frac{111-106}{5}=\frac{5}{5}=1\sigma

Therefore, 111 days is located 1 standard deviation to the right of the mean.

To find the percentage of pig pregnancies shorter than 111 days, we need to find the area covered to the left of 1 SD.

To find the area covered to the left of 1SD, we need to use the standard normal distribution table.

Based on the table, the area covered to the left of 1SD is 0.8413. Multiplying the area by 100, we get 84.13. Therefore, 84.13% of the pig pregnancies are shorter than 111 days.

5 0
1 year ago
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