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ser-zykov [4K]
3 years ago
7

Find the real or imaginary solutions of the equation by factoring. 6x^2+13x-5=0

Mathematics
1 answer:
beks73 [17]3 years ago
4 0
6x^2+13x-5=0\\
6x^2-2x+15x-5=0\\
2x(3x-1)+5(3x-1)=0\\
(2x+5)(3x-1)=0\\
x=-\dfrac{5}{2} \vee x=\dfrac{1}{3}
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Answer:

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Step-by-step explanation:

We are given these following functions:

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