<em>Acceleration (a) = 5.1 m/s</em>²
<em>Initial speed (u) = 16 km/h </em>⇒

<em>m/s </em>≈ <em>4.5m/s</em>
<em>
</em><em>Final speed (v) =118 km/h </em>⇒

<em>m/s</em> ≈ <em>32.8m/s</em>
<em>
</em>Distance(S) travel in that particular instant is carried out by 'Third equation of motion' i.e., v² = u² + 2aS
<em>So, When all quantities are in S.I. unit then,
</em>putting the values in the equation of motion,
<em /><em>As we have to carry out the distance covered,
</em><em>2</em>·<em>a</em>·<em>S = v</em>² <em>- u</em>²
<em>S = </em>

Putting values in derived equation,
⇒ <em>S = </em>

⇒ <em>S = </em>

⇒ <em>S = </em>

⇒ <em>S </em>≈ <em>103.489</em> <em>m
</em>
<em>
The total distance covered in that given condition is approx. 103.289 m.</em>
X² + 16x + 64 = 0
x² + 2 * x * 8 + 8² = 0
Now, sing the formula (a + b)² = a² + 2ab + b² , we get,
(x + 8)² = 0
Square rooting on both sides, we get,
x + 8 = √0
x + 8 = 0
x = - 8 <== that's your answer!!!
Answer:
below
Step-by-step explanation:
4(3 + 1)(3 + 3)(3 + 5)(3 - 5)
4(4)(6)(8)(-2)
16(-96)= -1536
Answer:
x = -2
Step-by-step explanation:
-3 = -13 - 5x
-3 + 13 = -5x
10 = -5x
10 ÷ (-5) = x
-2 = x
Answer:
The answer to your questions is: 25 new teachers
Step-by-step explanation:
Data
# of students = 2000
ratio = 3:80 teachers to students
New teachers = ?
Process
I suggest to use rule of three to solve this problem
3 teachers ---------------- 80 students
x ---------------- 2000 students
x = (2000 x 3) / 80 = 75 teachers
Number of initial teachers = 75
The ratio change to 1:20
1 teacher ------------------- 20 students
x ------------------- 2000 students
x = (2000 x 1) / 20
x = 100 teachers
Number of new teachers = 100 - 75 = 25