Answer:
Operational excellence
Explanation:
Operational excellence is the execution of a business strategy more consistently and reliably than the competition.
Smooth delivery of services and reliability are key factors that are used to measure operational excellence in businesses.
<em>The question is simply to test the understanding of the various concepts in business management .</em>
Package delivery and phone companies are businesses that relate directly with the general public, and they have a lot of competition. To thrive, they need operational excellence which covers the effective and consistent satisfaction of their customers.
Answer:
2^11
Explanation:
Physical Memory Size = 32 KB = 32 x 2^10 B
Virtual Address space = 216 B
Page size is always equal to frame size.
Page size = 16 B. Therefore, Frame size = 16 B
If there is a restriction, the number of bits is calculated like this:
number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]
where
physical memory size = 32KB which is the restriction
n bit machine = frame size = 16
Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11
Answer:
Choose internet is the right answer
Answer:
The Internet began as a US Department of Defense network named Advanced Research Project Agency Network (ARPANET) funded by the Advanced Research Project Agency (ARPA, later DARPA). In the 1970s, universities and other educational institutions began sharing this technology. The network grew as more and more users began sharing information.However, the information being shared on this network was very limited because of its government ties. The ARPANET was decommissioned in 1990. This move was followed by the commercialization of the Internet, which allowed it to carry business and personal traffic.
Explanation:
Answer:
Explanation:
The following pseudocode for this method using operations of the ADT list would be the following
swap(aList, indexI, indexJ) {
initialize temp_variable = Retrieve(indexI, aList)
Insert(Retrieve(indexJ, aList), indexI, aList)
Insert(Retrieve(indexI, aList), temp_variable, aList)
}
This code basically saves the aList index of i , into a temporary Variable. Then it sets the aList index of i to the value of the element in index of j. Then it does the same for the index of j with the tem_variable. If we assume that the indexes of i and j exist, then it can crash our entire program if those indexes are missing from the list when we try to access them.
