Answer:
int counter = 0;
String userInput = "";
while (userInput != "stop") {
print "What pet do you have? ";
userInput = readInputLine();
if (userInput != "stop" ){
counter = counter + 1;
print "\nYou have one ";
print userInput;
print ". Total # of Pets: ";
print counter;
}
}
Explanation:
not sure what programming language you use, therefore the answer is pseudocode but it should give you an idea how to implement a piece of code for this problem.
Also, from the way you described the exercise I'm not sure if you always are supposed to reply with "you have one" + the pet or if you should count how often the same pet was entered.
Answer: I cant give you an exact answer, but your options are gonna be B or C.
Explanation: A computer programmer actually doesn't work with a marketing company at all, most of them work from home as it is. And a Tech Support Specialist may work with a marketing firm, but it would be strictly IT stuffs.
It is true because it is really a good practise to save a presentation before printing it
Answer:
Check the explanation
Explanation:
An integer (int) is of two different bytes and each page has 200 bytes in length. What this means is that each row of array A (100 int) will fits perfectly in a page.
(a) For the initial or first array-initialization loop, one column is processed at a time, so a page fault will be generated at every inner loop iteration, with a total of 100*100=10,000 page faults.
(b) And when it comes to the second array-initialization loop, one row is processed at a time, and a page fault is generated at every outer loop iteration, with a total of 100 page faults.
Hence second array-initialization loop, has better spatial locality.
